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Compton Scattering Angle - CM FRAME

  • #1
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Homework Statement


Given incoming photon has energy 10Mev and scatters at angle 25 degrees, find the scattering angle in CM frame.


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Homework Equations




The Attempt at a Solution


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In lab frame, let the energy of incoming photon be ##E##. Total 4-vector would be ##P + Q = (\frac{E}{c},\frac{E}{c}) + (mc,0)##.

Using compton scattering formulas, I solved the scattering angle of electron ##\alpha = 35 ^o##, energy of scatted electron ##E_e = 4.02 ~MeV##, energy of scattered photon ##E' = 5.47~MeV##.


Having solved this completely in the lab frame before/after scattering, how do I proceed in CM-frame?

In CM frame, total momentum is ##0##, so 4-vector would be ##P_{cm} + Q_{cm} = (\frac{E_{p,cm}+E_{e,cm}}{c},0)##.

Even when I assume that in CM frame they are both scattered along the same line it doesn't help.
 

Answers and Replies

  • #2
vela
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Did you mean ##\alpha=35^\circ## or is that a typo?

Since you know everything the lab frame, you can simply use the Lorentz transformation to find the four-vectors in the CM frame. Suppose the CM moves with speed ##\beta=v/c##. Get expressions for the three-momentum of the photon and the electron in the CM frame. As you noted, their sum should be 0, which will allow you to determine ##\beta##.
 
  • #3
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Solved.
 

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