Special Relativity Math Thing (Fresnel's Drag Coefficient)

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Homework Help Overview

The discussion revolves around a potential discrepancy in a textbook regarding the expression for a variable in the context of special relativity and Fresnel's drag coefficient. Participants are examining the implications of using different forms of the variable, specifically comparing x = v/c and x = v/(nc).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the correctness of a term in their textbook, suggesting an alternative expression. Other participants discuss the significance of the index of refraction and its impact on the order of magnitude of the expressions in question.

Discussion Status

The conversation is ongoing, with some participants providing insights into the relevance of the index of refraction and its typical value. There is no explicit consensus on the original poster's concern, but the discussion is exploring the implications of the different expressions.

Contextual Notes

Participants note that the index of refraction, n, is typically close to 1 in many scenarios, which may influence the interpretation of the expressions being discussed.

Mark Zhu
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Homework Statement
Because v<<c in this case, we can expand the denominator
(1 + x)^-1 = 1 - x + ... keeping only the lowest term in x
v/c. The above equation becomes...
Relevant Equations
(1 + x)^-1 = 1 - x + ...
I am wondering if there is a typo in my textbook. Please see the attachment. The textbook says "...keeping only the lowest term in x = v/c." I am wondering if it should be "x = v/(nc)," as I circled in blue on the left side. It is a binomial expansion of the denominator. Shouldn't x be v/(nc) instead of v/c? The textbook says "...keeping only the lowest term in x = v/c." Thank you.
 

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It doesn't make any difference. ##\frac v c## and ##\frac v {nc}## have the same order of magnitude.
 
What do you mean same order of magnitude? Isn't n the index of refraction?
 
Mark Zhu said:
What do you mean same order of magnitude? Isn't n the index of refraction?
It's ##\frac v c## that is important. You probably have ##n \approx 1## in any case.
 
Thank you for your help
 

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