Special relativity, summation agreement

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SUMMARY

The discussion focuses on the proper use of indices in the context of special relativity, specifically regarding the equation involving the metric tensor. Uku initially misapplied the indices after the second equal sign, leading to confusion about the summation convention. The correct formulation is established as dx_{\mu} = g_{\mu \nu} dx^{\nu}, which indicates that the repeated index \nu requires summation. The final expression ds^2 = dx^{\mu} dx_{\mu} = dx^{\mu} g_{\mu \nu} dx^{\nu} clarifies the relationship between the differential distance and the metric tensor.

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Uku
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Homework Statement



[PLAIN]http://www.hot.ee/jaaniussikesed/valem_kovar_erlt.bmp

The first half of the equation is okay, but, after the second equal sign I started to improvise, did I mess up or is it correct? Trying to understand the indexes.

ds being the differentially small distance between events, dx the location vector? (not a 4 vector, I'm not sure on the English here) with covariant and contra-variant components present and the g is the metric tensor with its components marked by the indexes.

Regards,
Uku
 
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so i think you have got your indicies a little mixed up, a reapeted indicex, means to sum over the index, so start with
[tex]dx_{\mu} = g_{\mu \nu} dx^{\nu}[/tex]

so in this case the sum is over the repeated [itex]\nu[/itex], the sum would then become a double sum
[tex]ds^2 = dx^{\mu} dx_{\mu} = dx^{\mu} g_{\mu \nu} dx^{\nu}[/tex]

see this for more
http://en.wikipedia.org/wiki/Raising_and_lowering_indices
 
Thanks!
 

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