# Special relativity

1. Mar 20, 2012

### Lizwi

What is E = $\frac{m_{0}c^{2}}{1-v^{2}/c^{2}}$

2. Mar 20, 2012

### Nabeshin

Hi Lizwi,

I think you are missing a square root in the denominator? The expression:
$$E= \gamma m c^2 = \frac{mc^2}{\sqrt{1-v^2/c^2}}$$
Is the relativistic expression for the total energy of a moving body.

3. Mar 20, 2012

### genericusrnme

What Nabeshin said
You can also drop the 0 from the $m_0$, I've not seen the term 'rest mass' used since highschool. Once you're out of highschool it simply becomes mass as far as I know :p

4. Mar 21, 2012

### granpa

its a term that pops up in the four-momentum if you use the convention that x0 = ct rather that x0 = t

if you use x0 = t then you just get p0 = gamma*m