Special theory of relativity, theoretical problem

Click For Summary
SUMMARY

The discussion centers on a theoretical problem involving the special theory of relativity, specifically the concept of "proper time." Spaceship A travels at 0.7c and sends a message capsule to spaceship B, which is moving at 0.8c. The capsule itself travels at 0.9c. Participants clarify that proper time is measured by a clock at rest with respect to the object in question, while coordinate time is measured by an observer. Understanding these distinctions is crucial for solving the problem presented.

PREREQUISITES
  • Understanding of special relativity concepts, particularly "proper time" and "coordinate time."
  • Familiarity with relativistic speeds, specifically values expressed as fractions of the speed of light (c).
  • Basic knowledge of spacetime and how events are measured in relativity.
  • Conceptual grasp of inertial frames of reference in physics.
NEXT STEPS
  • Study the implications of proper time in special relativity.
  • Learn about the Lorentz transformations and their role in calculating time dilation.
  • Explore the concept of simultaneity in different inertial frames.
  • Investigate practical applications of special relativity in modern physics, such as GPS technology.
USEFUL FOR

Students of physics, educators teaching relativity, and anyone interested in the theoretical aspects of spacetime and time measurement in relativistic contexts.

Kennedy
Messages
70
Reaction score
2

Homework Statement


Spaceship A, traveling past us at 0.7c, sends a message capsule to spaceship B, which is in front of A and is traveling in the same direction as A at 0.8c relative to us. The capsule travels at 0.9c relative to us. A clock that measures the proper time between the sending and receiving of the capsule travels: a) in the same direction as the spaceships at 0.7c relative to us b) in the opposite direction from the spaceships at 0.7c relative to us c) in the same direction as the spaceships at 0.8c relative to us d) in the same direction as the spaceships at 0.9c relative to us e) in the opposite direction from the spaceships at 0.9c relative to us

Homework Equations


None.

The Attempt at a Solution


There's not much math involved in solving this problem, and it's all theoretical, but I think I'm missing a lot of something here. I don't even know where to begin when thinking about this question. Would the correct time simply be measured by the one that is moving at the exact same speed and direction as the capsule, but why?
 
Last edited:
Physics news on Phys.org
Kennedy said:

The Attempt at a Solution


There's not much math involved in solving this problem, and it's all theoretical, but I think I'm missing a lot of something here. I don't even know where to begin when thinking about this question. Would the correct time simply be measured by the one that is moving at the exact same speed and direction as the capsule, but why?

The key word in the question is "proper" time. What do you know about proper time?
 
PeroK said:
The key word in the question is "proper" time. What do you know about proper time?
Honestly, I don't know anything. I don't understand if it means proper time as in measured by us... I just don't understand. Is proper time measured by a clock that is said to be at rest with respect to the object?
 
Kennedy said:
Honestly, I don't know anything. I don't understand if it means proper time as in measured by us... I just don't understand. Is proper time measured by a clock that is said to be at rest with respect to the object?

Yes, that's the proper time of the capsule, which is also the spacetime distance between the events of the capsule being sent and received.
 
  • Like
Likes Kennedy
Kennedy said:
I don't understand if it means proper time as in measured by us...

If an observer is involved their proper time would be called "coordinate" time as far as the experiment is concerned. "Proper" time would be the time of a particle or object involved in the experiment. That's the conventional terminology.
 
  • Like
Likes Kennedy
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
12K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K