Specific Heat Capacity Graph Question

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SUMMARY

The discussion centers on the correct representation of a specific heat capacity graph for a phase change from liquid to solid, as outlined in the OCR G484 exam paper. The key points include the necessity of a horizontal line during the change of state, which indicates a constant temperature while the substance freezes. The mark scheme specifies that the graph should feature a negative gradient from 18°C to 0°C, followed by a horizontal line, and then a steeper negative gradient from 0°C to -18°C. The consensus is that the initial interpretation of the graph was incorrect due to the omission of the horizontal line representing the phase change.

PREREQUISITES
  • Understanding of specific heat capacity and phase changes
  • Familiarity with graphical representation of thermodynamic processes
  • Knowledge of the OCR G484 physics curriculum
  • Basic principles of energy transfer in thermodynamics
NEXT STEPS
  • Review the concept of phase changes in thermodynamics
  • Study the graphical representation of specific heat capacity and temperature changes
  • Examine the OCR G484 mark schemes for additional context on common errors
  • Learn about the relationship between kinetic energy and temperature in phase transitions
USEFUL FOR

Students preparing for the OCR G484 physics exam, educators teaching thermodynamics, and anyone interested in understanding specific heat capacity and phase change graphs.

YES q THE zU19
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Homework Statement


My answer is question 3 part c the graph. SHC = c
http://www.ocr.org.uk/Images/61757-question-paper-unit-g484-the-Newtonian-world.pdf [See page 7]

Homework Equations


E=mcdelta theta Power=Energy/Time Therfroe
Power*Time = Mass*c*delta theta.

The Attempt at a Solution


See in my coursebook similar question types have a horizontal line for when internal energy increases andpotential energy is constant.

So my graph looks like a constant line, followed by a decreasing gradient followed by a constant line on the x-axis horizontally foloweed by a line of decreasing gradient where the 2nd decreasing gradient line is less than the first.

Essentially my shape is like a reclining chair if you can visualise this.

However the mark scheme says this:

1. 18 oC to 0 oC negative gradient line

2. horizontal line on time axis

3. 0oC to -18 oC line of steeper –ve gradient (judged by eye) than in 1

The examiners report also says this:

The most common error being ignoring the horizontal line during the change of state. Most candidates recognised that the line for the frozen milk needed to be steeper.

From this would you say my graph is right or not as described above, they seem to omit the constant lines for when kinetic energy is constant.
 
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In my judgment, the book's answer is right and yours is wrong. I have no idea why your are referring to kinetic energy in this context. I also have no idea why you have a constant line to start with, unless you are referring to the time before the cooling begins. And I don't understand why you say that the gradient is decreasing, when the problem statements clearly says that heat is removed at a constant rate.
 
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Chestermiller said:
In my judgment, the book's answer is right and yours is wrong. I have no idea why your are referring to kinetic energy in this context. I also have no idea why you have a constant line to start with, unless you are referring to the time before the cooling begins. And I don't understand why you say that the gradient is decreasing, when the problem statements clearly says that heat is removed at a constant rate.

Thank you for your reply. I figure it out. There was only one change of state from liquid to solid, hence one horizontal line to show this.

Regards
 

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