1. The problem statement, all variables and given/known data When a car brakes, an amount of thermal energy equal to 112500J is generated in the brake drums. If the mass of the brake drums is 28 kg and their specific heat capacity is 460.5 Jkg^-1K^-1? A piece of iron of mass 200g and temperature 300°C is dropped into 1.00kg of water of temperature 20°C. What will be the eventual temperature of the water? Specific Heat Capacity of iron is 450Jkg^-1 K^-1, water 4200Jkg^-1 K^-1 2. Relevant equations Q=m c delta t Q=c detla t 3. The attempt at a solution (112500/28)/460.5 = 8.7 °C (4200+450)/(300+20)=14.53°C I am 99% sure that I got the first one right, however I don't think the second one is right because no one knew exactly how to do that one from my class. Could you guys steer me in the right direction :) ?