- #1
mtjces said:Homework Statement
See picture.
Homework Equations
The Attempt at a Solution
I've decomposed F1 into F1x F1y and F1z..
F1x = 150 * sqrt 3
F1y = 150
F1z =150 * sqrt 2[
Now I'm stuck../QUOTE]
I don't know what sort of parallelogram you drew, but this is a 3-D kinda problem.mtjces said:Homework Statement
See picture.
Homework Equations
The Attempt at a Solution
I tried drawing a parallelogram, but it didn't help, so I'm stuck. I'd need an idea in the right direction, if possible.
SteamKing said:I don't know what sort of parallelogram you drew, but this is a 3-D kinda problem.
gneill said:I'm not seeing how you've accomplished your decomposition of F1. The magnitude of the vector comprised by those components would be about 367 N, which is larger than the given magnitude of F1. So you might want to re-think your method (whatever that was...).
The diagram is very helpful because it gives you the angles between F1 and each of the coordinate axes. This should make finding the projections of F1 on each of the axes easy to find.
For the Z component the angle was not 60 degrees. What does the diagram show it to be? Do you expect the Z-compoennt to be less than or greater than zero?mtjces said:F1z = cos 60 * 300N = 150N
F1x = cos 45 * 300N = 150*sqrt2 N
F1y = cos 60 * 300N = 150 N
Would this be correct?
You'll want to write a vector equation that expresses your desired result. Fix your F1 vector first though.I'm confused about the next step..
gneill said:For the Z component the angle was not 60 degrees. What does the diagram show it to be? Do you expect the Z-compoennt to be less than or greater than zero?
Check your value for cosine 45 degrees. A cosine should not be > 1.
You'll want to write a vector equation that expresses your desired result. Fix your F1 vector first though.
Yes, that looks right. The z-component is negative because the vector F1 is directed below the x-y plane.mtjces said:F1z = cos 120 * 300N = -0.5 * 300N = -150N (but how does that make sense?)
cos 45 = (√2)/2
so F1x = 300 N * cos 45 = 150 N * √2 = 150√2 N
F1y = cos 60 * 300N = 150 N
Is this right now?
gneill said:Yes, that looks right. The z-component is negative because the vector F1 is directed below the x-y plane.
gneill said:Yes, but sort out your component subscripts. You've listed F2z twice. It would help if you put them in standard order, too: x, y, z. Otherwise, I think you're there.
You don't know how to calculate the magnitude from the three force components?mtjces said:F2x = -150√2 N
F2y = 650 N
F2z = 150 N
How do I calculate F2?
mtjces said:F2x = -150√2 N
F2y = 650 N
F2z = 150 N
How do I calculate F2?
Sorry, messed up x:mtjces said:F2 = √((-150√2)^2 + 150^2 + 650^2) = 700 N
To calculate the angles of F2 I used:
cos x = (F2x/F2) = (-150√2 N / 700 N) ---> x = 72.36°
cos y = (F2y/F2) = (650N / 700 N) ---> y = 21.79°
cos z = (F2z/F2) = (150N / 700 N) ---> z = 77.63°
Correct?
The magnitude of a force is the measure of its strength or intensity. It is typically measured in units of Newtons (N) in the metric system or pounds (lbs) in the imperial system.
The magnitude of a force can be calculated by multiplying the mass of an object by its acceleration, using the equation F=ma. Alternatively, it can also be calculated using trigonometric functions if the force is acting at an angle.
An angle in the context of force refers to the direction in which the force is acting. It is typically measured in degrees or radians and can be used to determine the direction and orientation of the force.
The angle of a force can be specified using a reference point or axis, such as the x-axis or y-axis. It can also be specified using the direction of motion or the location of the force relative to an object.
Specifying both the magnitude and angle of a force is important because it provides a complete description of the force and its effects. It allows us to accurately calculate the resulting motion or changes in an object, and helps us understand the forces at play in a given system.