This is my first post here, I am going for high college physics, this is my second physics class in my life. (One in highschool and this is Physics 100 -- Survey of Physics.) We do all our homework online, so here's the first one.. A person walks first at a constant speed of 3.40 m/s along a straight line from Point A to Point B and then back along the line from B to A at a constant speed of 5.60 m/s. What is (a) her average speed over the entire trip? For average I simply did 3.4+5.6 = 9 Then I did 9/2 (Two different speeds) and I got 4.5.. but for some reason it's showing up wrong on my webassign. Is there something small I'm missing? Any help would be appreciated. Second Question A sky diver, with parachute unopened, falls 625 m in 15.0 s. Then she opens her parachute and falls another 358 m in 168 s. What is her average velocity (both magnitude and direction) for the entire fall? Magnitude m/s So for the free fall v = (a)(t) and because a = g in this instance I did v = (9.8)(15.0) = 147 m/s So for the free fall velocity = 147 The second part is confusing, The parachute is open so a != 9.8 because of the wind drag on the chute, does a = 1/2gt^2? Cause if it does I think I can figure it out. Thanks for your help in advance.