Speed Average Velocity Change Question

Click For Summary

Homework Help Overview

The discussion revolves around calculating average speed and average velocity in physics problems involving motion. The original poster presents two scenarios: one involving a person walking at different speeds and another involving a skydiver. Participants explore the concepts of average speed and velocity, questioning the methods used to calculate them.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of average speed by questioning the method of simply averaging two speeds. They suggest using the relationship of distance traveled divided by time instead. The original poster also raises confusion about applying formulas for the skydiver's fall and the rocket's ascent, particularly regarding time and acceleration.

Discussion Status

Some participants have provided guidance on how to approach the calculations for average speed and velocity. There is ongoing exploration of different interpretations of the problems, particularly regarding the application of formulas and the understanding of motion concepts.

Contextual Notes

The original poster expresses uncertainty about the time and distance traveled in the walking scenario, which affects their ability to calculate average speed. Additionally, there are constraints related to homework rules that may limit the types of assistance sought.

  • #31
Nope, it's much simpler than that. If "d" is the one way distance, what's the round trip distance?
 
Physics news on Phys.org
  • #32
Doc Al said:
Nope, it's much simpler than that. If "d" is the one way distance, what's the round trip distance?

2d ;) .

1234567890
 
  • #33
Yes (finally!)

Now use the total time and distance to find the average speed.
 
  • #34
Well I did d(1/5.6 + 1/3.4)

I got d(.472).. but I don't know a number for distance so I can't multiply that out..

:(
 
  • #35
You don't need a number for the distance (or the time for that matter). Take the expression for total distance that you found and divide it by the expression for total time.
 
  • #36
Doc Al said:
You don't need a number for the distance (or the time for that matter). Take the expression for total distance that you found and divide it by the expression for total time.

Ok

Expression for total distance = 2d
Expression for total time = d(.472)

2d / d(.472)

d / (.472)
 
  • #37
Kildars said:
Expression for total distance = 2d
Expression for total time = d(.472)
OK.
2d / d(.472)
OK.

d / (.472)
Not OK. What happened?

Ahh... I see what you might have done. Note, in general:
\frac{2a}{a} \ne a
 
  • #38
Doc Al said:
OK.

OK.


Not OK. What happened?

Ahh... I see what you might have done. Note, in general:
\frac{2a}{a} \ne a

(2)(.472) = 4.23

Correct answer, wow thanks.

Could you explain a little bit more how that works? Because without your assistance I wouldn't have been able to get that correct.
 
  • #39
Not sure what I could explain about it further. It looked to me that you were thinking of subtraction instead of division: 2a - a = a, but 2a/a = 2. Big difference.

More important is to revise your problem solving strategy. As this problem illustrates, sometimes you don't need information that you think you need. When in doubt, label the unknown and keep on going!
 
  • #40
I didn't mean the division issue, I meant the whole problem.. :)
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
Replies
20
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
5
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K