Speed of a mass falling into a star given the mass and radius of the star

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SUMMARY

The discussion centers on calculating the speed of a mass falling into a star using the gravitational constant and the star's mass and radius. The formula applied was the square root of ((2)(6.67*10^-11)(3.90E+30))/(5.70E+7), which resulted in an incorrect value of 1.55*10^-5. Participants emphasized the importance of using correct units in calculations to achieve accurate results.

PREREQUISITES
  • Understanding of gravitational physics
  • Familiarity with the gravitational constant (6.67 x 10^-11 m^3 kg^-1 s^-2)
  • Knowledge of mass and radius measurements in astrophysics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the concept of gravitational acceleration and its calculations
  • Study the application of units in physics equations
  • Learn about the implications of mass and radius on gravitational forces
  • Explore advanced astrophysics topics related to stellar dynamics
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Students and educators in physics, astrophysics enthusiasts, and anyone interested in gravitational calculations and their applications in celestial mechanics.

TobiasZed
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Homework Statement
Beginning at rest at an extremely large separation, a ball is released and allowed to fall toward a star of mass 3.90E+30 kg and radius 5.70E+7 m. What is the speed of the ball when it reaches the surface?
Relevant Equations
square root of (2*G*M)/(r)
I tried the square root of ((2)(6.67*10^-11)(3.90E+30))/(5.70E+7)
I got 1.55*10^-5 and that is wrong. Maybe I am using the wrong equation but this is the one of professor gave me and I don't know what I am doing wrong :-(
 
Physics news on Phys.org
Check your calculation.
 
… and use units!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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