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Speed of Block after Newton's Second Law

  1. Mar 3, 2013 #1
    1. The problem statement, all variables and given/known data

    http://postimage.org/image/6exf0w475/

    B)
    I have a question on this part. Would I just use the "v = v0 at" equation here because the question states "after it starts moving?" Do i need to include static/kinetic friction into this equation somehow?

    2. Relevant equations

    part a) Newton's Second Law

    part b) v=v0 at

    3. The attempt at a solution

    For part A, I found the acceleration to be (Tcos∂-((mg-Tsin∂)*[itex]\mu[/itex]k)) / m

    For part B I'm thinking that I use "v = v0 at" but the "after it starts moving" part of the question confuses me. Does it mean that v0 would be 0?
     
  2. jcsd
  3. Mar 3, 2013 #2

    Doc Al

    User Avatar

    Staff: Mentor

    That's fine. (Where you use T instead of F.)

    Yes, v0 = 0. The equation you mean is v = v0 + at.
     
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