Speed of light in Non-Inertial reference frame?

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The speed of light is consistently measured as c in local experiments, even in non-inertial reference frames, despite the complexities introduced by acceleration. Observers in non-inertial frames may perceive discrepancies in light's travel time due to their frame's motion, as illustrated by the Sagnac effect. While the coordinate speed of light can vary in non-inertial frames, the local measurement remains constant. Theoretical discussions suggest that electromagnetic waves could exhibit behaviors akin to refraction in curved spacetime, but these effects are negligible with current technology. Ultimately, the speed of light retains its defined value in local measurements, aligning with the principles of relativity.
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I see a lot of places, "The speed of light is the same in all inertial reference frames." But is it the same in non-inertial reference frames too?
For example, your reference frame/observer is accelerating according to someone else holding a flash light, at the moment they meet, the other person turns on the flash light, will the accelerated person observe the light as c as well?

I assume the speed of light is the same for ANY reference frame, non-inertial frames as well, but would like to here what you guys think.
 
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The coordinate speed of light need not be constant in non-inertial frames. When this question has come up on other threads like this one, some people have argued that if an accelerating observer measures the speed of light locally using physical rulers and clocks accelerating along with him, he'll still get c, although I'm not sure I agree with this since an accelerating ruler can't necessarily remain rigid depending on the type of acceleration so I don't see how there'd be any single correct way to define how far apart a given set of ruler-markings are.
 
In non-inertial reference frames light still always follows null geodesics. In that swnsw the speed of light is always c even in non-inertial frames. As JesseM said the coordinate speed need not be c.
 
FAQ: Is the speed of light equal to c even in an accelerating frame of reference?

The short answer is "yes."

The long answer is that it depends on what you mean by measuring the speed of light.

In the SI, the speed of light has a defined value of 299,792,458 m/s, because the meter is defined in terms of the speed of light. In the system of units commonly used by relativists, it has a defined value of 1. Obviously we can't do an experiment that will remeasure 1 to greater precision. However, it could turn out to have been a bad idea to give the speed of light a defined value. For example, it would have been a bad idea to give the speed of sound a defined value, because the speed of sound depends on extraneous variables such as temperature.

One such extraneous variable might be the direction in which the light travels, as in the Sagnac effect, which was first observed experimentally in 1913. In the Sagnac effect, a beam of light is split, and the partial beams are sent clockwise and counterclockwise around an interferometer. If the interferometer is rotating in the plane of the beams' path, then a shift is observed in their interference, revealing that the time it takes light to go around the apparatus clockwise is different from the time it takes to go around counterclockwise. An observer in a nonrotating frame explains the observation by saying that the beams went at equal speeds, but their times of flight were unequal because while they were in flight, the apparatus accelerated. An observer in the frame rotating along with the apparatus says that clearly the beams could not have always had the same speed c, since they took unequal times to travel the same path. If we insist on letting c have a defined value, then the rotating observer is forced to say that the same closed path has a different length depending on whether the length is measured clockwise or counterclockwise. This is equivalent to saying that the distance unit has a length that depends on whether length is measured clockwise or counterclockwise.

Silly conclusions like this one can be eliminated by specifying that c has a defined value not in all experiments but in local experiments. The Sagnac effect is nonlocal because the apparatus has a finite size. The observed effect is proportional to the area enclosed by the beam-path. "Local" is actually very difficult to define rigorously [Sotiriou 2007], but basically the idea is that if your apparatus is of size L, any discrepancy in its measurement of c will approach zero in the limit as L approaches zero.

In a curved spacetime, it is theoretically possible for electromagnetic waves in a vacuum to undergo phenomena like refraction and partial reflection. Such effects are far too weak to be detected by any foreseeable technology. Assuming that they do really exist, they could be seen as analogous to what one sees in a dispersive medium. The question is then whether this constitutes a local effect or a nonlocal one. Only if it's a local effect would it violate the equivalence principle. This is closely related to the famous question of whether falling electric charges violate the equivalence principle. The best known paper on this is DeWitt and DeWitt (1964). A treatment that's easier to access online is Gron and Naess (2008). You can find many, many papers on this topic going back over the decades, with roughly half saying that such effects are local and violate the e.p., and half saying they're nonlocal and don't.

Sotiriou, Faraoni, and Liberati, arxiv.org/abs/0707.2748

Cecile and Bryce DeWitt, "Falling Charges," Physics 1 (1964) 3

Gron and Naess, arxiv.org/abs/0806.0464v1
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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