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## Homework Statement

At time t=0, a proton is a distance of 0.360 meters from a very large insulating sheet of charge and is moving parallel to the sheet with speed 990 meters/second . The sheet has uniform surface charge density 2.34 * 10^-9 (C/M^2).

What is the speed of the proton at 7.10×10^−8 seconds?

## Homework Equations

E = 1/(4pi(ε_0))*(|Q|/r^2)

q=σA

Charge of proton = 1.6*10^-19

F=ma=Eq

## The Attempt at a Solution

I'm not really sure how to approach the problem as the textbook chapter examples only relate to solving problems relating to gauss's law, electric field, charge density and electric flux.

I tried assuming the question wants me to solve for E (electric field) using 1.6*10^-19C as the charge Q, and distance .36 meters. Then went back into F=ma = Eq and found a value for acceleration and plugged into V = v_0 + a(t) however the answer was incorrect.