What is the correct velocity of an electron in a bound orbit around a proton?

  • Thread starter Thread starter LukasMont
  • Start date Start date
  • Tags Tags
    Electron Speed
Click For Summary
SUMMARY

The discussion focuses on calculating the velocity of an electron in a bound orbit around a proton, specifically at a distance of 2 x 10^-8 cm. The user equates the centrifugal force (Fc = v²/r) and the electrostatic force (Fe = e²/r²) to derive the electron's velocity. The initial calculation yields an incorrect velocity of 11.5 x 10^-6 cm/s, prompting requests for clarification. Key errors identified include incorrect unit handling and a miscalculation in the final step.

PREREQUISITES
  • Understanding of classical mechanics, specifically centrifugal force.
  • Knowledge of electrostatics, particularly Coulomb's law.
  • Familiarity with the cgs (centimeter-gram-second) system of units.
  • Basic algebra for solving equations involving physical constants.
NEXT STEPS
  • Review the principles of centrifugal force and its application in circular motion.
  • Study Coulomb's law and its implications for electrostatic interactions.
  • Learn about unit conversions within the cgs system to avoid common pitfalls.
  • Practice solving similar problems involving forces in atomic-scale systems.
USEFUL FOR

Students and educators in physics, particularly those focusing on atomic structure and electrostatics, as well as anyone interested in classical mechanics applications in quantum contexts.

LukasMont
Messages
6
Reaction score
3
Good evening!

The question states: 9. Electron in bound orbit about proton. Suppose that an electron moves in a circular orbit about a proton at a distance of 2 X l0^-8 cm. Consider the proton to be at rest. (a) Solve for the velocity of the electron by equating the centrifugal and electrostatic forces.

Considering that the elementary charge (charge of the electron is e = 4.8 x 10^-10 statcoloumbs), working on the cgs system, I equated the centrifugal force Fc=v²/r and the eletrostatic force Fe= e²/r². My way of solving the problem was:

Fc=Fe,
v²/r = e²/r²
v²= e²/r
v= (e²/r)¹/²
v= (2.3x10^-19/2x10^-8)¹/²
v = 11.5x10^-6 cm/s.

Which is clearly a way down from the correct value. Could anyone please help me?

Thanks!
 
Physics news on Phys.org
LukasMont said:
Fc=v²/r
Is the electron mass 1 g? Always write out the units!
 
Also your last calculation step is wrong. v = (11.5x10-12)1/2 which is not 11.5x10-6. But see also Orodruin's comment.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
22
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
13
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K