Charged particle in Electric and Magnetic field

  • Thread starter Vibhor
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  • #26
ehild
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Sorry . I think It should be ##x=\frac{v_1m}{qB}sinωt## only . I don't see why there should be a minus sign .
x is correct. I meant z, sorry.
 
  • #27
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##z = - \frac{v_1m}{qB}(1-cosωt) ## ??
 
  • #28
ehild
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##z = - \frac{v_1m}{qB}(1-cosωt) ## ??
Yes.
 
  • #29
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Ok .

x will be 0 when ##\frac{qBt}{\pi m }## is an integer , y will be 0 at ##t = \frac{2mv_2}{qE}## , z will be 0 when ##\frac{qBt}{2\pi m }## is an integer
 
  • #30
ehild
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Ok .

x will be 0 when ##\frac{qBt}{\pi m }## is an integer , y will be 0 at ##t = \frac{2mv_2}{qE}## , z will be 0 when ##\frac{qBt}{2\pi m }## is an integer
What integer is it? When is z = 0? And all of them should be zero at the same time.
 
  • #32
ehild
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  • #33
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Was it difficult?

It surely was until you took over :smile: . Honestly speaking , I had almost made up my mind to leave this problem as I was completely clueless :headbang:. But last couple of hours of problem solving were pretty exciting :partytime:,thanks to you .

You are amazing :bow:.
 
  • #34
ehild
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It was the combination of a circular motion in the x,z plane and a vertical projectile motion in the direction of y. The period of the circular motion should be the same as the flight time of the vertical projectile.

upload_2016-5-10_11-18-29.png



Thank you for the thanks :smile:
 
Last edited:

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