Sphere falling through viscous material - velcoity calc

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SUMMARY

The discussion focuses on calculating the velocity of a sphere falling through a viscous fluid, starting from a known height and initial velocity. The terminal velocity can be determined using Stokes' Law, considering the fluid's density and viscosity, as well as the sphere's density. The key challenge is to derive the velocity as a function of time, recognizing that the acceleration is not constant due to the fluid's resistance. An exponential term is involved in the equation, which approaches terminal velocity as time approaches infinity.

PREREQUISITES
  • Understanding of Stokes' Law for terminal velocity calculations
  • Familiarity with Newton's second law of motion
  • Knowledge of fluid dynamics, particularly viscosity and density concepts
  • Basic calculus for solving differential equations
NEXT STEPS
  • Research the derivation of the velocity function for objects in viscous fluids
  • Learn about the application of differential equations in motion analysis
  • Explore numerical methods for solving non-linear equations in fluid dynamics
  • Study the effects of varying fluid properties on terminal velocity
USEFUL FOR

This discussion is beneficial for physicists, engineers, and students studying fluid dynamics, particularly those interested in motion through viscous materials and terminal velocity calculations.

Bakery87
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I'm dropping a sphere from a known height, and it enters a viscous fluid. I know the initial velocity as it enters the fluid, from there I need the velocity as it falls through the fluid (as a function of time).

I know it should approach it's settling velocity (terminal velocity) and from there I can use stokes law to get the terminal velocity. What I need is the velocity as it approaches that point. Assuming no spin of the sphere. I know the fluid's density and viscosity, sphere density, and initial velocity as it enters the fluid.

I can find this equation for a skydiver falling through the air, but since the air has very little viscosity it does not contribute to the buoyancy of the skydiver.
 
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You don't think about terminal velocity from the start. Just find out the velocity as a function of time. I remember there is an exponential term in it. If you substitute t as infinity in the equation, you get the terminal velocity.

Hint- Its acceleration will not be constant. From Newton's second law Fnet = ma, here a=dv/dt.
 

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