Spheres, Plates, and Gauss' Law

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SUMMARY

The discussion focuses on calculating electric fields using Gauss' Law for a uniformly charged sphere and a flat conducting plate. For the sphere with a radius of 8.0 cm and a volume charge density of 500 x 10^-9 C/m^3, the electric field at a distance of 3.0 cm is calculated to be approximately 564.7 N/C. For the flat conducting plate with a surface charge density of 8.0 x 10^-9 C/m^2, the electric field 10 µm away is determined to be 904 N/C. Both calculations confirm the application of relevant equations and principles of electrostatics.

PREREQUISITES
  • Understanding of Gauss' Law and electric fields
  • Familiarity with volume charge density and surface charge density concepts
  • Knowledge of the constants k (Coulomb's constant) and ε₀ (permittivity of free space)
  • Ability to perform basic calculus and integration for electric flux
NEXT STEPS
  • Study the derivation and applications of Gauss' Law in electrostatics
  • Learn about electric field calculations for different charge distributions
  • Explore the concept of electric flux and its relation to charge enclosed
  • Investigate the effects of surface charge density on electric fields in conductors
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by charged objects.

Soaring Crane
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Homework Statement



A sphere of radius 8.0 cm carries a uniform volume charge density rho = 500*10^-9 C/m^3. What is the electric field at r = 3.0 cm?

a.36.0 N/C

b.230 N/C

c.140 N/C

d.565 N/C

e.450 N/C




Homework Equations



E = (k*Q*r)/(R^3), where R = sphere’s radius and r is distance inside sphere

The Attempt at a Solution


V = (4/3)*pi*(0.08 m)^3 = 0.00214 m^3
Q = p*V = (500*10^-9 C/m^3)*(0.00214 m^3) = 1.07*10^-9 C

E = (k*Q*r)/(R^3), where R = sphere’s radius and r is distance inside sphere

E = (8.988*10^9)*(1.07*10^-9 C)/(0.03 m^2) = 564.7 N/C




Homework Statement



A large, flat conducting plate has a surface charge density sigma = 8.0*10^-9 C/m^2 on one of its surfaces. What is the magnitude of the electric field 10 µm from this plate?


a.72 N/C

b.0.23 kN/C

c.0.90 kN/C

d.90 MN/C

e.9.0 1012 N/C



Homework Equations



electric flux = Integral[E*A] = Q_enclosed/epsilon_0

The Attempt at a Solution



E*A_plate = q/epsilon_0
E*A_plate = (sigma*A_plate)/(epsilon_0)

E = sigma/epsilon_0 = (8.0*10^-9 C/m^2)/(8.85*10^-12) = 904 N/C

Thanks.
 
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