Solving for Net Charge on Inner Surface of Conducting Shell

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The net charge on the inner surface of a conducting shell surrounding a charged sphere is -Q, induced by the +Q charge of the sphere. When a charge is placed outside the shell, the inner surface charge becomes -2Q to maintain neutrality, countering the external field. The use of the equation E=F/q is questioned for solving these problems, but the focus remains on charge distribution. If the sphere and shell are not concentric, the net charge on the inner surface remains the same, although the external charge's influence is clarified. The discussion emphasizes understanding charge interactions and the implications of external charges on the system's neutrality.
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Homework Statement



(1)A conducting sphere w/ charge +Q is surrounded by a spherical conducting shell.
What is net charge on inner surface of the shell?

(2) A charge is placed outside the shell.
What is the net charge on the inner surface now?

(3) What if the shell and sphere are not concentric, will this change your answers?


Homework Equations



E=\frac{F}{q}


The Attempt at a Solution



I've done some reading from 2 different books on the same topic, and I've gotten some info from other similar problems on PF. I still feel like I need work on this section, any help is appreciated. Thanks.

(1) The inner sphere will induce a -Q charge on the interior surface of the shell, and a +Q on the outer surface.

(2) This one has me stumped: I figure that the interior surface of the shell must become -2Q with the introduction of a point charge outside. I think since its a conducting shell, the charge inside must be zero, and as a result it must create an e-field that can counter the fields of both charges, in order to remain neutral. Could I use the equation E=\frac{F}{q}, to help me solve this problem?

(3) If the sphere and shell are not concentric, the results should be the same since we're dealing with the net charge on the interior surface.
 
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In (2), you seem to assume that the external charge is equal the internal. That is not how the problem is stated.
 
Sorry, the problem uses q for the point charge outside, and +Q for the charge of the sphere. I'm not exactly sure if they're suppose to be the same, but if we assumed they were not equivalent, would the charge of the interior surface in (2) be -(Q+q)? Thanks
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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