Spherical coordinates, vector field and dot product

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The discussion focuses on determining whether the vector fields A and B are parallel by analyzing their dot product. It emphasizes that a dot product of 1 does not necessarily indicate parallelism, as vectors can have a dot product of 1 while being non-parallel. The angle between the two vector fields is clarified to be either 0 or 180 degrees for them to be parallel, with 90 degrees indicating perpendicularity. Participants discuss the implications of the angle and the correct interpretation of the spherical coordinates involved. Ultimately, the conversation highlights the importance of accurately calculating the dot product and understanding the relationship between the vectors' angles.
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Homework Statement



Show that the vector fields A = ar(sin2θ)/r2+2aθ(sinθ)/r2 and B = rcosθar+raθ are everywhere parallel to each other.

Homework Equations


\mathbf{A} \cdot \mathbf{B} = |\mathbf{A}||\mathbf{B}|\cos(0)

The Attempt at a Solution



So, if the dot product equals 1. They should be parallel correct?

A={sin(2θ)/(r2),2(sin(θ)/r2),0}
B={rcos(θ),r,0}

if this is the dot product how do I determine the angle between the vectors?
(2 Sin(θ))/r + (Cos(θ) Sin(2 θ))/r

Do i need to transform to rectangular coordinates?
 
Last edited:
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Rombus said:
|A||B|=ABcosθ

You'll want to double check this equation :wink:
So, if the dot product equals 1. They should be parallel correct?

Careful, \mathbf{i}+2\mathbf{j} and \mathbf{i} are not parallel, but their dot product is 1. Likewise, \mathbf{i}+\mathbf{j} and 2\mathbf{i}+2\mathbf{j} are parallel but their dot product is not equal to 1.

If 2 vector fields are parallel, what can you say about the angle between them at every point? What does the dot product formula then tell you?
 
Hello, thanks for the reply. I blame lack of sleep on my dot product equation mishap. :zzz:

So, the angle between the vector fields is 90 degrees and the dot product would be 0 correct?
 
Rombus said:
Hello, thanks for the reply. I blame lack of sleep on my dot product equation mishap.

So, the angle between the vector fields is 90 degrees and the dot product would be 0 correct?

:zzz: a 15 minute nap can sometimes do a world of good for one's studies :wink:

If the angle between two vector fields is 90 degrees, then they are perpendicular, not parallel:wink:
 
of course! Okay, so the angle is zero or 180. So upon finding the dot product how would I determine the angle between these two fields from the result of this dot product? (2 Sin(θ))/r + (Cos(θ) Sin(2 θ))/r

Do I just plug in zero for theta?
 
Rombus said:
of course! Okay, so the angle is zero or 180.

Wouldn't 180 degrees mean the vector fields were anti-parallel?:wink:

So upon finding the dot product how would I determine the angle between these two fields from the result of this dot product? (2 Sin(θ))/r + (Cos(θ) Sin(2 θ))/r

Do I just plug in zero for theta?

No, the θ in the equations for your 2 vector fields is either the polar angle (the angle between the position vector and the polar axis) in spherical coordinates, or the azimuthal angle (the angle between the projection of the position vector onto the xy-plane, and the x-axis), depending on which naming convention you are using for spherical coordinates.

That θ is, in general, not the same as the angle between the two vector fields.

If the angle between the two vector fields is 0, then the (correct) dot product equation tells you \mathbf{A} \cdot \mathbf{B} = |\mathbf{A}||\mathbf{B}|\cos(0)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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