Spherical star in a hydrostatic equilibrium

ted1986
Messages
22
Reaction score
0
Hello again,

I've got a question about a star in a hydrostatic equilibrium.
How do I derive an equation of motion for a pertubation in the full momentum equation? I'm attaching my solution (my_solution.jpg) , but I'm not quite sure about it.

The full exercise is attached as astro_problem.jpg.

Thank you.
 

Attachments

  • astro_problem.jpg
    astro_problem.jpg
    36.7 KB · Views: 661
  • my_solution.jpg
    my_solution.jpg
    16.8 KB · Views: 655
Astronomy news on Phys.org
It's not that simple, the meaning of "d" and "delta" are different. The meaning of "d" is "a change as you change location", but the meaning of "delta" is "perturbed from the original equation." So before you substitute and delta expressions, you first have to find the momentum equation that applies to the delta variables. When you're all done, you'll still have d/dr kinds of things, but they will apply to the delta variables, not the P and rho by themselves.
 
I think I did this once. I even thought it was my idea. Don't use their hints, see attachment. The "del" works like del f = f' del r.
 

Attachments

  • dada.jpg
    dada.jpg
    14 KB · Views: 496
Helios said:
I think I did this once. I even thought it was my idea. Don't use their hints, see attachment. The "del" works like del f = f' del r.



OK, I tried to solve the exercise as you said (P=K*rho^[tex]\gamma[/tex]), but the equaion I've got seems to be to complicated... (my derivation is attached - star_my_sol2.jpg)

Perhaps the derivation needed to solve it is less complicated?

Thank you.
 

Attachments

  • star_my_sol2.jpg
    star_my_sol2.jpg
    29.5 KB · Views: 500
Sorry, but that's way off because the way you related density and mass. Your equation would only work for mean density, were M the total mass. Their relationship is instead differential.
The knack here is to apply the variation ( perturb ) and then factor out ( linearize ) the del-r out. Since the variation is arbitrary, the parenthetical stuff must equal zero ( the derived equation ).
I don't get the hints they gave.
 

Attachments

  • dada02.jpg
    dada02.jpg
    24.8 KB · Views: 534
Thank you for your efforts :)
 

Similar threads

  • · Replies 49 ·
2
Replies
49
Views
6K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 15 ·
Replies
15
Views
12K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K