Sphericial Capacitance w/Dielectrics

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Homework Help Overview

The discussion revolves around calculating the capacitance of a spherical capacitor composed of two insulating spherical shells with different dielectric strengths, situated between two metallic shells and separated by a vacuum gap. Participants are exploring the relationships between charge, potential difference, and capacitance in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the total capacitance using integrals to calculate the potential difference across different regions (dielectrics and vacuum). Questions are raised about the correctness of the expressions used and the treatment of charge in the equations.

Discussion Status

There is an ongoing exploration of the mathematical expressions involved in calculating the capacitance. Some participants have provided feedback on the approaches taken, suggesting adherence to a systematic method without shortcuts. The discussion reflects a collaborative effort to verify the correctness of the derived equations.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the amount of direct assistance provided. There is a focus on ensuring that the reasoning and assumptions made in the calculations are critically examined.

mitleid
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A spherical capacitor is made of two insulating spherical shells with different dielectric strengths, k1 and k2, situated between two spherical metallic shells and separated by a vacuum gap. Calculate the capacitance of this system.

graph2.jpg


Total C = Q(free) / \DeltaV where \LambdaV is the varied potential between the two metal shells.

\LambdaV = \int^{a}_{d}E(r)dr = - \int^{a}_{b}[(1/4*pi*Eps) * (1/k1)*(Qfree / r^2) * dr] - \int^{b}_{c}[(1/4*pi*Eps) * (Qfree / r^2) * dr] - \int^{c}_{d}[(1/4*pi*Eps) * (1/k2) * (Qfree / r^2) * dr]

Q free will be negated in the final equation, since C = Q/V and V includes Q in its numerator (hope that makes sense). So after integrating V through each of the mediums, the two dielectrics and the vacuum, I get the sum :

Ctotal = = Ke[C(dielectric 1) + C(vacuum) + C(dielectric 2) = Ke[(1/k1)*(1/a - 1/b) + (1/b - 1/c) + (1/k2)*(1/c - 1/d)]

Is this correct?
 
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mitleid said:
A spherical capacitor is made of two insulating spherical shells with different dielectric strengths, k1 and k2, situated between two spherical metallic shells and separated by a vacuum gap. Calculate the capacitance of this system.

graph2.jpg


Total C = Q(free) / \DeltaV where \LambdaV is the varied potential between the two metal shells.

\LambdaV = \int^{a}_{d}E(r)dr = - \int^{a}_{b}[(1/4*pi*Eps) * (1/k1)*(Qfree / r^2) * dr] - \int^{b}_{c}[(1/4*pi*Eps) * (Qfree / r^2) * dr] - \int^{c}_{d}[(1/4*pi*Eps) * (1/k2) * (Qfree / r^2) * dr]

Q free will be negated in the final equation, since C = Q/V and V includes Q in its numerator (hope that makes sense). So after integrating V through each of the mediums, the two dielectrics and the vacuum, I get the sum :

above looks good.

Ctotal = = Ke[C(dielectric 1) + C(vacuum) + C(dielectric 2) = Ke[(1/k1)*(1/a - 1/b) + (1/b - 1/c) + (1/k2)*(1/c - 1/d)]

Is this correct?

how did you get this part? stick to what you were doing above... get delta V... then take Q/delta V... don't take any shortcuts...
 
I did this next...

delV = - (Qfree/(4*pi*Eps)) [ \int^{a}_{b} (dr/(k1*r^2)) + \int^{b}_{c} (dr/r^2) + \int^{c}_{d} (dr/(k2*r^2))

The general form of the solution for int(dr/r^2) is -(1/r). This let's the pre-existing negative cancel out, and I just have to substitute to get the expression I have above... I've got it written down, just didn't want to type it all out. :)

Also, the solution I came up with should be equal to 1/Ctot, not just Ctot. I think that's right...
 
mitleid said:
I did this next...

delV = - (Qfree/(4*pi*Eps)) [ \int^{a}_{b} (dr/(k1*r^2)) + \int^{b}_{c} (dr/r^2) + \int^{c}_{d} (dr/(k2*r^2))

The general form of the solution for int(dr/r^2) is -(1/r). This let's the pre-existing negative cancel out, and I just have to substitute to get the expression I have above... I've got it written down, just didn't want to type it all out. :)

Also, the solution I came up with should be equal to 1/Ctot, not just Ctot. I think that's right...

Yes, exactly that was 1/Ctot. everything looks good.
 

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