Spivak's Calculus on Manifolds problem (I). Integration.

Click For Summary
SUMMARY

The discussion focuses on proving the Jordan-measurability of a subset C within a rectangle A in 0, there exists a partition P of A such that the difference between the upper and lower sums of the characteristic function of C is less than ε. The key equations involve the characteristic function χ_C(x) and the conditions under which the boundary of C has measure zero, which is essential for the proof.

PREREQUISITES
  • Understanding of Jordan-measurable sets
  • Familiarity with characteristic functions
  • Knowledge of upper and lower sums in integration
  • Concept of measure zero and its implications in analysis
NEXT STEPS
  • Study the properties of Jordan-measurable sets in
  • Learn about the implications of measure zero boundaries in integration
  • Explore the concept of partitions in the context of Riemann integration
  • Investigate the relationship between characteristic functions and integrability
USEFUL FOR

Students and researchers in mathematical analysis, particularly those focusing on integration theory and measure theory, will benefit from this discussion.

ELESSAR TELKONT
Messages
39
Reaction score
0

Homework Statement



If A\subset\mathbb{R}^{n} is a rectangle show tath C\subset A is Jordan-measurable iff \forall\epsilon>0,\, \exists P (with P a partition of A) such that \sum_{S\in S_{1}}v(S)-\sum_{S\in S_{2}}v(S)<\epsilon for S_{1} the collection of all subrectangles S induced by P such that S\cap C\neq \emptyset and S_{2} the collection of all subrectangles S induced by P such that S\subset C.

Homework Equations



C is Jordan-measurable iff \partial C has measure zero.
The characteristic function of a set C is the function \chi_{c}(x)=\left\{\begin{array}{cc}1 &x\in C\\ 0 &x\notin C\end{array}\right .

The Attempt at a Solution



I have tried to proof directly (that means I suppose Jordan-measurable). Let \epsilon>0. Then I use the fact that if C is Jordan-measurable then \chi_{C}(x) is integrable in A. That means that U(\chi_{C},P)-L(\chi_{C},P)<\epsilon.

Now I could write U(\chi_{C},P)=\sum_{S\in S_{1}}v(S)+\sum_{S\in S_{2}}v(S) because the supremum of the function at S_{1} and S_{2} is 1. In the same manner L(\chi_{C},P)=\sum_{S\in S_{2}}v(S) because the infimum of the function at S_{1} and S_{2} is 0,1 respectively... Here my proof brokes since U-L as I have written U and L is U-L=\sum_{S\in S_{1}}v(S)<\epsilon. I have no idea how to put into that the other sum. Any help that you can provide is precious.
 
Physics news on Phys.org
Does the boundary of C have content zero? That may be the angle to start from (at least for the implication that assumes C is Jordan-measurable).
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
16
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
32
Views
4K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K