Spring Car, Acceleration Problem: Find Spring Constant

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The discussion focuses on calculating the spring constant needed for a spring car to accelerate from rest to 20 m/s at least 50 times before needing to be rewound. The initial calculations suggest a spring constant of 5.7 * 10^7 N/m based on force and displacement. However, it is pointed out that the energy released by the spring increases with the square of the displacement, meaning the initial unwinding provides more energy than subsequent unwinding. This indicates that the approach should shift from force calculations to energy considerations for accurate results. The conversation emphasizes the importance of understanding energy dynamics in spring mechanics.
Jaccobtw
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Homework Statement
You devise a wound up car powered by a spring for trips to the grocery store. The car has an inertia of 500 kg and is 4.2 m long. It should be able to accelerate from rest to 20 m/s at least 50 times before the spring needs winding. The spring runs the length of the car, and a full winding compresses it to half of its length In order to meet the acceleration requirement, what must the value of the spring constant be?
Relevant Equations
F = ma
F = -kd
"It should be able to accelerate from rest to 20 m/s at least 50 times before the spring needs winding"
-So F = -kd = -k(2.1) - d is 2.1 because it is the compression length

Now, since we know the d, divide it by 50, 2.1/50 = 0.042m

Basically, the spring unwinds 0.042 m 50 times for a total distance of 2.1m.

Now, calculate acceleration:
v(f)^2 = v(i)^2 * 2 * a * d

We know our final velocity is 20 m/s, our initial is 0.

Solving for a we get, 4,762 m/s^2

Back to our original equations

F = -kd = ma

Solve for k and we get : 5.7 * 10^7 N/m

But I got this wrong :(
 
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Jaccobtw said:
the spring unwinds 0.042 m 50 times
No. The energy stored in a spring rises as the square of the displacement, so the first 0.042 m it unwinds releases more energy than the next 0.042 m, etc.
Instead of forces, work with energy.
 
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