Spring Constant and Compression Problem

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SUMMARY

The discussion centers on calculating the compression of a spring in a dart gun with a spring constant of 62.50 N/m and a potential energy of 0.540 J. The correct formula to use is the potential energy equation for springs, given by PE = 1/2 k x^2. The correct approach involves rearranging this equation to solve for x, leading to the conclusion that the spring compression is approximately 0.1 meters, not 9 meters as incorrectly suggested by one participant.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with potential energy equations
  • Basic algebra for rearranging equations
  • Knowledge of units of measurement in physics
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  • Review the derivation of the potential energy formula for springs: PE = 1/2 k x^2
  • Practice solving problems involving Hooke's Law and spring compression
  • Explore real-world applications of spring constants in mechanical systems
  • Investigate the effects of varying spring constants on energy storage
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Students studying physics, particularly those focusing on mechanics and energy, as well as educators looking for examples of spring-related problems.

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Homework Statement



The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.50 N/m, is 0.540 J. Find by how much is the spring is compressed.

Homework Equations



I know that F=-k*change in x and also spring= 1/2kx^2

The Attempt at a Solution



Using the two formulas above, i tried 1/2(62.5)(x^2) which is .540? but I am getting the wrong answer.. I also tried x=0 and canceling it. I am not sure what I am doing wrong here.
 
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What number did you get using the 2nd equation (don't use the first)? Please show your math. And why would you try x = 0?
 
I got 9.1125... i did 1/2(62.5)(.540^2)
 
I know X is the "displacement" but I am drawing a blank as to what that number is
 
Are you saying you solved (1/2)(62.6)x2=0.540 for x, and got the wrong answer?
 
I can tell you that the spring is not compressed 9 meters unless you have one big dart gun hehe. Looks like you have your numbers mixed up. Potential energy of a spring is equal to 1/2k*x^2 so your equation should look like this

.540=1/2k*x^2, x is how much the spring is compressed.
 

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