SUMMARY
The equilibrium length of a spring with a force constant of K = 260 N/m is 0.25 m. To hold the spring at twice its equilibrium length (0.50 m), the extension from the equilibrium position is 0.25 m. According to Hooke's Law (F = Kx), the force required to maintain this extension is calculated as F = 260 N/m * 0.25 m, resulting in a force of 65 N. This calculation confirms that the correct magnitude of the force needed is 65 N.
PREREQUISITES
- Understanding of Hooke's Law
- Basic knowledge of spring mechanics
- Ability to perform unit conversions and calculations
- Familiarity with force constants in physics
NEXT STEPS
- Study advanced applications of Hooke's Law in mechanical systems
- Explore the concept of potential energy stored in springs
- Learn about the effects of varying force constants on spring behavior
- Investigate real-world applications of springs in engineering
USEFUL FOR
Students studying physics, mechanical engineers, and anyone interested in understanding spring dynamics and force calculations.