Square Plate Parallel, with angle, Capacitance Problem

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SUMMARY

The discussion focuses on calculating the capacitance of two parallel plates, where one plate is angled at a small angle theta from the horizontal. The known capacitance formula for parallel plates, C = (E0 * A)/d, is established, with A being the area and d the separation distance. The user is advised to conceptualize the problem as a series of small capacitors in parallel along the angled plate, necessitating the use of integration to derive the capacitance approximation. A suggestion is made to visualize the setup with discrete capacitors to aid in formulating the integral.

PREREQUISITES
  • Understanding of capacitance formulas, specifically C = (E0 * A)/d.
  • Basic knowledge of calculus, particularly integration techniques.
  • Familiarity with trigonometric functions and their application in geometry.
  • Concept of electric fields and their relationship to capacitance.
NEXT STEPS
  • Learn how to set up integrals for calculating capacitance in non-standard geometries.
  • Study the application of trigonometric functions in determining distances in angled configurations.
  • Explore the concept of summation equations for discrete capacitor arrangements.
  • Investigate the effects of varying plate angles on capacitance values.
USEFUL FOR

Electrical engineers, physics students, and anyone involved in capacitor design or analysis, particularly in non-traditional configurations.

sdhick
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Given two parallel plates, length a. One being on the x axis, starting at the origin. The other starting a distance, d up the y-axis at an angle theta (parallel to the x axis), for theta being small. I need to find an equation for an approximation of the capacitance.


I know that if the two plates were purely parallel, C = (E0 * A)/d = (E0 * a^2)/d and that the equation I'm looking for should be (E0 * a^2)/d *( something )
And I know that I need to think of this as a chain of small infinite capacitance in parallel along the angled plate. Meaning I need to do an integral.


I however do not even know where to start. I don't want anyone to just give me the something, but I would love some help on where to start with the integral.

I'm thinking it will have to be and integral (not sure on the limits) of the E field dotted with the ds(or distance).

I would appreciate any help you can give me. Thanks in advance!
 
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sdhick said:
Given two parallel plates, length a. One being on the x axis, starting at the origin. The other starting a distance, d up the y-axis at an angle theta (parallel to the x axis), for theta being small. I need to find an equation for an approximation of the capacitance.


I know that if the two plates were purely parallel, C = (E0 * A)/d = (E0 * a^2)/d and that the equation I'm looking for should be (E0 * a^2)/d *( something )
And I know that I need to think of this as a chain of small infinite capacitance in parallel along the angled plate. Meaning I need to do an integral.


I however do not even know where to start. I don't want anyone to just give me the something, but I would love some help on where to start with the integral.

I'm thinking it will have to be and integral (not sure on the limits) of the E field dotted with the ds(or distance).

I would appreciate any help you can give me. Thanks in advance!

What a fun problem! I hadn't seen this one before.

You absolutely have the right idea -- that's how I would approach the problem. To help you set up the integral, start by drawing a small number of discrete caps, with the plates spaced farther and farther apart. I'd start with something like 4 cap plate pairs. Use that drawing to figure out what the y separation as a function of x is (it will be a trig function... which one?), and what the delta-x is (that relates to the area). Then see if that helps you set up the integral in the limit where delta-x shrinks to zero. Post your work here if it doesn't click for you and we'll help based on what you post.

Fun problem. Welcome to the PF.


EDIT -- an intermediate step if you need it, between the 4-cap drawing and the integral, would be to write a summation equation, showing the equation and the terms for the summation of those 4 capacitors.
 

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