Square Root Problem: Solving for m in s=k√(1+m)/(1-m) | Help & Tips

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Homework Help Overview

The problem involves solving the equation s=k√((1+m)/(1-m)) for the variable m. This falls under algebraic manipulation and equation solving within the context of square roots and rational expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various approaches to isolate the variable m, including dividing both sides by k, squaring the equation to eliminate the square root, and rearranging terms. There is also mention of potential tricks or methods that could simplify the process.

Discussion Status

The discussion is active, with participants providing suggestions on how to manipulate the equation. Some guidance has been offered regarding operations to eliminate the square root and isolate m, but there is no explicit consensus on the best approach yet.

Contextual Notes

Participants express uncertainty about the initial steps and the existence of tricks that may apply to solving the equation. There is a recognition that mathematical understanding plays a significant role in solving such problems.

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Homework Statement



s=k\sqrt{\frac{1+m}{1-m}} , solve for m

Homework Equations





The Attempt at a Solution



Honestly I am stumped, but I do know there is a trick to it. I can't quite remember, but it might have something to do with taking the reciperical or the inverse...maybe the conjugate? Just need a little help getting started.

Thanks,
Chris
 
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Something that would be helpful is to divide both sides by k.
The equation then becomes
<br /> \frac{s}{k} = \sqrt{\frac{1 + m}{1 - m}}<br />
Now, what operation gets rid of square roots?
 
Ok, got rid of the root by squaring. Now I have this. How can I isolate the m variable?

\frac{s^{2}}{k^{2}} = \frac{1+m}{1-m}
 
Multiply both sides by k2, then multiply both sides by (1 - m). If you expand both sides, you should be able to rearrange things to get the terms with m on one side, and all the others on the other side.
 
Something you said at the beginning deserves a comment:
Honestly I am stumped, but I do know there is a trick to it.
There are probably a few occasions where solving an equation requires some trick that you have to know, but most of the time it's done by plain old mathematical understanding.
 

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