Squeezing f(x) Between g(x) and h(x): Cos, Sin, & Tan

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Homework Help Overview

The discussion revolves around the application of the squeeze theorem to the function f(x) = x^4 cos(2/x^6). Participants are exploring how to establish bounding functions g(x) and h(x) to apply the theorem effectively.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to determine appropriate bounding functions for f(x) and question how to implement the squeeze theorem in this context. There is also a focus on the limits involved, particularly as x approaches zero.

Discussion Status

The discussion is ongoing, with some participants seeking clarification on the specific limit to which x is approaching. There is a mix of interpretations regarding the application of the squeeze theorem and the necessary bounding functions.

Contextual Notes

Some participants note the importance of defining the limit point clearly, as well as the constraints of the problem related to the behavior of the cosine function within the specified range.

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f(x)=x4 cos(2/x6)

g(x) <= f(x) <= h(x)

how to get g(x) and h(x) by using the squeeze theorem??

I know is something like this -1 <= x <= 1

But how do i implement it here, and especially to the cos, sin, and tan??
 
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solve the problem!
 
So in your question, x^4 . cos \frac{2}{x^6} what's the limit ie. as x approaches what? zero?

Then we can use the squeezing theorem; g(x) \leq f(x) \leq h(x)
Assuming that the limit of f(x) as x approaches c is L then;

lim_{x \rightarrow c} g(x) = lim_{x\rightarrowc} h(x) = L

Thus lim_{x \rightarrow c} f(x) = L
 
Last edited:
What exactly is the question? The "squeeze theorem" refers to limits but you are trying to find the limit of x4cos(2/x6) as x goes to what?


(And it is your responsibility to "solve the problem"!)
 

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