SR Simultaneous Lines Drawn in the Sand

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The discussion centers on Einstein's thought experiment regarding simultaneity in special relativity, specifically the scenario involving two light sources, A and B, and an observer in a moving frame. It is established that while stationary observers perceive the emissions from A and B as simultaneous, the moving observer O' does not, due to their motion towards B and away from A, resulting in a time difference in detection. Participants debate the implications of simultaneity, emphasizing that the timing of light detection is frame-dependent and not solely based on the observer's position at the moment of emission. The conversation highlights the fundamental principle that the speed of light is constant across all frames, leading to different conclusions about simultaneity based on relative motion. Ultimately, the discussion reaffirms that events simultaneous in one frame may not be so in another, underscoring the complexities of time perception in relativity.
  • #91
baffledMatt said:
When you ask each observer, how many of the answers do you think will be in exact agreement?




baffledMatt said:
Then I suppose your answer to my question 'how do you determine this universal frame' will be 'I define it that way'. Ok, have it your way. If you want you can define the 'correct' frame which is this funny democratic average of all the frames in the universe. However, imagine I decide on a different definition, say that where I am sitting is the only stationary frame and everything else revolves around me. Will there be any way you can tell me which of our definitions is correct? will there be any observations which will differ between the universe with my definition and the one with yours?

Just a slight interjection here. Aren't you both assuming you each know the direction to the "absolute frame"? Isn't there a way to solve this problem without being so universally esoteric? i don't want to deny any of you your say, but it seems slightly over the edge of relevence.
Before we get to your discussion points let us first dispose of the trivial.

1. Stipulation:SR theory predicts the photons emitted in the stationary frame in our experiment will predict the same photons were not emitted simultaneously in the moving frame.

2. PS-strips (photo-sensitive strips) located within 1 photon wave length of the sources of the photons emitted in the stationary frame are exposed (in the moving frame) as the photons are emitted. Super fast film, ps-strips << micorn wide, Each ps-strip locatable to the midpnt M' with mirror image ps-strip at other end within any mutuallly agreeable resolution.

Something's got to give.
Can SR defeat the observation ( that appears contradictory)?

Can the observation defeat SR.

If no observer in a moving frame then no problem, no discussion. Is the presence of the moving frame itself analyzable as a source of physical force that guarantees the photons will not be emitted simultaneously in the moving frame. As far as I can determine the alleged effect is purely one running directly from the postulates of SR exclusively.

Can you see my problem of understanding how a physical event, supported by my famous ps-strips can be modified, not by any real or imagined force, not even any quantum mechanical "nonlocal force channels" are implied or even speculated. The modification, as I call it, is brought into the reality of the universe by the mere presence of an observer. A million observers all moving at different angles all arrive at the same conclusion of nonsimultaneity, and all would have different calculated times for the emission of the photons.

If no moving platform we have a simple simultaneous event of photon emission. With observres, the only expeiemntal difference in the two situations, we have physical modification of an obsevable manifestly existent only by the presence of a moving platform.

If we look first only at the first postulate of SR that the laws of physics are invariant in all inetial frames, will someone please explain how in one frame an event is simultaneous but in another frame, inertial to be sure, that same physical event subject to the laws of physics being invariant in all inertial franes is an event that iss not simultaneous. ie the event in the moving frame is variant to the laws of physics in the moving frame? Maybe the rule is, there is just one exception to the invariance of physical law?

This is much lengthyer than your post and I wouldn't exoect an off the cuff answer. Pick and choose what you think is most important.


Not so. I put you into space in a spaceship with no windows. Is there any experiment you can carry out (without looking outside of course) which will allow you to determine whether you are moving or not?

Matt
what is wrong with looking outside?
 
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  • #92
i'm going to sum up my arguments for the time being and take an interlude.

it is entirely valid for the moving observer to claim the photons were not simultaneous because that is his perception of reality.

it's entirely valid for any stationary observer to say the photons WERE simultaneous because that is their perception of reality.

when you get 5.99 billion people to say, "yeh dude, those were simultaneous" you must be open to the possibility that perhaps your perception of reality is wrong BECAUSE you were the one moving, NOT everyone else

possibly the reason you guys are complaining so much is because it is TOO trivial :D

-peace for now
 
  • #93
jdavel said:
ram2048

Evidently you don't want to understand this theory. The nice thing about physics is that if you don't want to understand it, you won't!
jdavel please do us all one large favor, please.

Take two unambiguous subjects for analysis.

1.The opening thread stipulated that SR theory would predict the simultaneously emitted photons in the stationary frame would not be simultaneous in the moving frame. This given.

2. Photo-sensitve strips in the moviong frame were exposed by the subject photons when the photons were emitted. The locations of the exposed strips were efefctively exactly at A and B in the srationary frame an each srip, faction of a micron thick are sufficient in numbers on both ends of themoving platform such that the photons are guiarant3edd to be exposed whatever the shrinking of he moving platform. Finally, the ps-stips are identified in pairs where each pair is equal in distance from the midpoint M' of the moving frame, which was determined by the same physicallaws tha assured us that M was themidpoint of A and B in thre stationary frame. This is given,. We do not use the simultaneous arrival iof the photons as the source of the information taht M is the mispoint of the sources, nor in the calculations that SR used in the consklusion that were made, though theinforamtion couls be used. No reason to exclude it. But this was determined long before the experiment ran..

Refreshing your memory of the experiment, when M' was at M, the midpoint of the phioton sources at A and B, photons were emitted simulatneously in the stationary frame.

You can see the apparent copntradiction: Emitted photons simulatneously in the stationary platferom detected effectively instantaneously in the moving frame at the same instant the photons were emitted in the stationary frame.

Give us your veyr very best shot at analyzing the situation. Does SR defeat observation, pe se? IS there any physical law connecting the difference in simultaneity conclusion in the different frames? If physical laws arei invariant in inertial frames why is this exception allowed to continue in the language undiscussed?
 
  • #94
geistkiesel said:
Both observers send out 1 second pulses from their respective clock timing circuits. The slower frame's pulse rate is less than the fastest frame's pulse rate and vice versa, right? This was off the top of my head a few days ago. I have used it and have had no reply,but is seems like it should work.

No, if they are sending the same 1 second pulses to each other they will each observe exactly the same thing - either a slowing down of the pulses (red shift) or a speeding up (blue shift) depending whether they are moving toward each other or away from each other.

Some have suggetsed that no, the moving frame cannot guarantee I can find the midpoint of the ps_strip. My counter, which I havwen;'t seen challenged, is I used the same law of physics that allowed the stationry framwe to determine themisddle of he photon sources at A and B.

I still don't see exactly what you mean by this. Could you perhaps give me the dumbed down version of how exactly this is done? It's no good you saying 'using the same physics' since we evidently don't agree on exactly what the physics is!

Can you see my position when I want to say that the photons were mesured in the moving frame equal distances from the midpoint of gthe moving frame when the pulses were emitted by A and B. Just can you see my reasonaning. I will not hold you to an adnmiission that I am right and you are adnmitting error. Only can yo see why I might say that?

I can see why you might think that - I remember having exactly these sorts of problems with SR. The way I would always go about solving these problems though was to sit down and just calculate the thing. To illustrate:
Let's make some definitions:
x : space coordinate in 'stationary' frame. x = 0 is the midpoint between A and B, which are located at x = -L and x = L respectively.

v : velocity of the moving observer relative to the stationary observer.

Ok, so now I will calculate what the 'stationary' observer sees. Note I am not going to use any SR as such. We first calculate the location of the point where the 'moving' observer and the light from A coincide. This happens at a time t_A after the light is emitted from A and the point where they meet we denote d_A. By equating the distance the light moves in this time to the distance the moving observer moves we have:

vt_A = d_A
ct_A = d_A + L
so
\frac{v}{c}(L + d_A) = d_A
and
d_A = \frac{\frac{v}{c}L}{(1-\frac{v}{c})}

Similarly, we can derive d_B which is the point where the moving observer meets the light from B
vt_B = d_B
ct_B = (L-d_B)
so
\frac{v}{c}(L-d_B) = d_B
and again
d_B = \frac{\frac{v}{c}L}{(1+\frac{v}{c})}

Evidently, d_A \neq d_B so the photons do not hit the moving observer at the same time/place.

I am saying I do not have to argue time dilation, shrinking absolte space and time , noe of that. Why? I have agreed in the results of SR. Whi amI or you for that matter to be chosen as the obne who arbitrates what is physical law? Me saying SR will predict such and such doesn't make the poustulates true, the posstulates stand ot dall on their pwn merist.

Ok, now repeat the calculation above, but for the moving observer. The only SR result I want you to use is that each observer must observe the same value for the speed of light. If you do this you should see that you need things like time dilation and lack of simultaneity to resolve the observations.

Matt
 
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  • #95
ram2048 said:
i'm going to sum up my arguments for the time being and take an interlude.

it is entirely valid for the moving observer to claim the photons were not simultaneous because that is his perception of reality.

it's entirely valid for any stationary observer to say the photons WERE simultaneous because that is their perception of reality.

when you get 5.99 billion people to say, "yeh dude, those were simultaneous" you must be open to the possibility that perhaps your perception of reality is wrong BECAUSE you were the one moving, NOT everyone else

possibly the reason you guys are complaining so much is because it is TOO trivial :D

-peace for now

But to you they really weren't simultaneous and those 5.99 billion people (who, understanding relativity,) admit that they're simultanity may not be your simultanity.
 
  • #96
ram2048 said:
i'm going to sum up my arguments for the time being and take an interlude.

it is entirely valid for the moving observer to claim the photons were not simultaneous because that is his perception of reality.

it's entirely valid for any stationary observer to say the photons WERE simultaneous because that is their perception of reality.

when you get 5.99 billion people to say, "yeh dude, those were simultaneous" you must be open to the possibility that perhaps your perception of reality is wrong BECAUSE you were the one moving, NOT everyone else

possibly the reason you guys are complaining so much is because it is TOO trivial :D

-peace for now

Amen, a moment of silence for ram2048 conclusions, if you please.

In my country, a free country, we have the freedom of thought to perceive as we do, nay as we will. One is allowed the freedom, yes just one person in a crowd of 70,000 say, is allowed the unconditional freedom to perceive pink elephants doing the moon walk, where all others, the 49,999 all perceive the running of the Kentucky Derby. Why do the people scream as they do when watching horse races, you might ask? Because tt makes the horses run faster.

ram2048, take a well deserved few days off. Perchance the bubbling thoughts in the myriad of vortexes in the mind will produce an moe enlightened way of describing what is so clear to others, namely this writer, and what is becoming clear to the host body of scientists.

Tis trivial is it? as a physics problem, I agree. However, the economics of the trivial physics problem poses a nontrivial barrier: Who will cover all the professional funeral expenses of the SR disenfrancised? I am not familiar with the insuance coverage in the theoretical physics industry, but surely these matters must have been discussed in the past, you know, a sudden demise of a preciously held physical theory, like when an observational guillotine suddenly falls foom on a high and . . . .?? Surely everybody is covered, aren't you?
 
  • #97
ram2048 said:
it is entirely valid for the moving observer to claim the photons were not simultaneous because that is his perception of reality.

it's entirely valid for any stationary observer to say the photons WERE simultaneous because that is their perception of reality.

Ok, I can safely say we agree here :smile:

when you get 5.99 billion people to say, "yeh dude, those were simultaneous" you must be open to the possibility that perhaps your perception of reality is wrong BECAUSE you were the one moving, NOT everyone else

The laws of nature are not a democracy! If you want to have one frame more 'correct' than another there must be a real physical difference so that you can determine which frame this is.

Why can't both perceptions be correct? You have the idea that there is some 'true' reality of whether or not these events were simultaneous. SR is trying to tell us to forget this notion, there is no way we can tell which frame is 'correct', so we shouldn't try to consider it.

Matt
 
  • #98
Alkatran said:
But to you they really weren't simultaneous and those 5.99 billion people (who, understanding relativity,) admit that they're simultanity may not be your simultanity.

Alkatran, pray tell man, is simultaneity a characteristic of humanity? Or, on the other hand, is simultaneity a righteous physical phenmomenon? Must one understand SR befoe simultaneity is physically real? In the same sense does my undersatnding of the laws of gravity the assurance I need in order not to drift over to Bakersfield California for instance? I have to know and understand the laws of gravity, you're suggesting in order to avoid Bakersfield, California? My god man, think of the consequences.
 
  • #99
geistkiesel said:
2. PS-strips (photo-sensitive strips) located within 1 photon wave length of the sources of the photons emitted in the stationary frame are exposed (in the moving frame) as the photons are emitted. Super fast film, ps-strips << micorn wide, Each ps-strip locatable to the midpnt M' with mirror image ps-strip at other end within any mutuallly agreeable resolution.
Something's got to give.

Ok, so we have these film strips and after the experiment they will have two little dots on them corresponding to the points A and B when the photons were emitted. In the moving frame we measure the distance between these points using a metre ruler and come up with a length. We have (using my previous notation) that in the stationary frame the distance between A and B is 2L. However, due to Lorentz contraction the stationary observer will observe the moving observer to measure this distance to be 2L\gamma

NB
\gamma = \frac{1}{\sqrt(1-\frac{v^2}{c^2})} &gt; 1

This is because he sees the moving observer trying to measure a distance of 2L with a shorter (contracted) measuring stick. So he is observing the moving observer making a measurement larger than 2L.

The moving observer on the other hand sees the distance between A and B contracted. Hence, naively you might think he will measure a length of 2L/\gamma. This cannot be because what each observer sees must be the same (remember that we just had the stationary observer seeing the moving observer measure a longer length), so somehow the moving observer must also measure 2L\gamma. This happens because he does not observe the photon emissions to be simultaneous. Hence there is a little bit of time between the first and the second photon, which makes his measured length larger. This will ensure that his observation coincides exactly with that of the stationary observer.

Matt
 
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  • #100
ok here we go.

suppose in the future we all live in space and drive spacecars around (whee fun)

suppose i get into an accident with another driver in a spacecar who happened to be stopped at a spacestopsign.

now on his UPS (universal position system) his data is telling him that by triangulating the positions of key points in the solar system he was "globally accepted" to be at rest in relation to the rest of the solar system.

MY UPS has the entire universe moving in relation to me.

when the cop comes by in his space cop car, do you think my defense of "relatively, he rammed me as well" is going to stand up in court?

what if spacecars were only built in such a way that they can only go FORWARDS, leaving absolutely NO DOUBT that i DID rear-end the other guy?
 
  • #101
Keep in mind that the principle of relativity is part of classical mechanics; it was not invented by Einstein for the purpose of developing SR.



And to drive home the cosmological point about there being no good point of reference, consider these:

(1) Suppose in your future that we also considered a similar accident occurring on the streets of future earth. In this case, neither car was stationary with respect to the solar system!


(2) The guy who stopped was not at rest with respect to the rest of the universe. And, for instance, you might have been at rest with respect to the Milky Way. The important point is that a particular frame of reference was chosen (in this case, "at rest WRT the solar system"), so the traffic law is defined relative to this choice.


(3) What is "at rest in relation to the rest of the solar system" anyways? Things are moving in all sorts of directions, accelerating all over the place.
 
  • #102
geistkiesel said:
Alkatran, pray tell man, is simultaneity a characteristic of humanity? Or, on the other hand, is simultaneity a righteous physical phenmomenon? Must one understand SR befoe simultaneity is physically real? In the same sense does my undersatnding of the laws of gravity the assurance I need in order not to drift over to Bakersfield California for instance? I have to know and understand the laws of gravity, you're suggesting in order to avoid Bakersfield, California? My god man, think of the consequences.

An understanding and acceptance of relativity would probably help in understanding (or convincing, depending on your point of view.. how relative) that my simultanity isn't your simultanity.

I only said that even if those billions of people perceived the event, they wouldn't say it was simultaneous for others if they believed in relativity.
 
  • #103
baffledMatt said:
Ok, so we have these film strips and after the experiment they will have two little dots on them corresponding to the points A and B when the photons were emitted. In the moving frame we measure the distance between these points using a metre ruler and come up with a length.

No we use reflected light pulses and set the ps-strips the same way that M was established as the midpoint od A and B. As we have an excess of ps-strips whose width << lamba(photon), i.e. sub micron ranges, SR shrinking is not a concern. We can rig it so that the number of ps-strips are two or three orders of magnitude less than the photon wave length. Overlap and overmesure o an overkill degree.

baffledMatt said:
We have (using my previous notation) that in the stationary frame the distance between A and B is 2L. However, due to Lorentz contraction the stationary observer will observe the moving observer to measure this distance to be 2L\gamma
\gamma = \frac{1}{\sqrt(1-\frac{v^2}{c^2})} &gt; 1

This is because he sees the moving observer trying to measure a distance of 2L with a shorter (contracted) measuring stick. So he is observing the moving observer making a measurement larger than 2L.

Not quite. As we have an excess of ps-strips, we assure ourselves that whatever shrinking occurs, one strip will be colocated at A and B within a minimum acceptable errror. The numbered ps-strips guarantees the location of mesurements being equal distant from M' established by relected laser measurements. The frame knows nothing of stationary observers, perceptions or even that an experiment is being conducted. What the stationary observer sees does not imply the use of gamma for any useful purpose. WE want to deermine if the simultabeous emission of photons mitted in the stationary frame are emitted simultaneously in the moving frame. And this is all is it not?

The moving and stationary observers each have the planet's best SR and Dissident SR physicists to assure the most rabid sceptic, either way, that A = A' , M = M' and B = B' when the photons are emitted and detected by the ps-strips to a resolution << perturbations due to shrinking effects. Remember, we are only verifying simultaneous emission of photons in the moving frame or not. We need not concern ourselves what observes are noting about the frames cordinates.


baffledMatt said:
The moving observer on the other hand sees the distance between A and B contracted. Hence, naively you might think he will measure a length of 2L/\gamma. This cannot be because what each observer sees must be the same (remember that we just had the stationary observer seeing the moving observer measure a longer length), so somehow the moving observer must also measure 2L\gamma.

No quite. We are not concerned with what observers see. The human element is totally irrelevant. No one is making corrections based on seeing another across the way doing anything like making a measurement.

baffledMatt said:
This happens because he does not observe the photon emissions to be simultaneous. Hence there is a little bit of time between the first and the second photon, which makes his measured length larger. This will ensure that his observation coincides exactly with that of the stationary observer.
I don't see this at all. If the stationaray observer, knowing the photons are emiotted simultaneously in his frame, as a given, (OK for this we'll put a stationary observer at A and B, temporarily,), how pray tell can the stationary obsever also see the photons emitted a little time later, just to stay synchronuzed to SR theory?in between? It can't be done baffledMatt, there is no such stationary observer in the universe. this cannot be done.

If you insist on this as strenuously as you are able look what you are arguing. The mere fact that the moving frame is present as we described it places a physical delay in photon emission where if no moving frame passes, the photons are emitted simultaneously. They are still emitted simultabneously, but again, two times. Do you suspect a conservation of energy problem here baffledMatt,? A physical event forced on the physical laws by postulated imperative? Is there any phsyical law, such as that SR descriibed that is invariant under all this? You are left with a shrug of the shoulders and " that's the way it is", arent't you? Also, the stationary observer has a certificate of the experimental conditions that the photons are emitted simultaneously in the stationary frame. How can the mere presence of the moving frame alter the sequence? Can it be both ways? Human observers within eyelashes of each other see the same physical event occurring at different times? When the observers see the photon and raise their hand in recognition, you say each observer raises their hand at diffeent moments, and the stationary observer sees this? Incredible, isn't it baffledMatt? While they are staring each other in the face? Bam, the photons are emitted, then bam, they are emitted again? This is SR theory applied to force experimental observation being consistent with theory, it is called a mathematical contrivance with no physical analog attached. These results are looked at weeks after the experiment. No observer has "seen" any other observer measure anything. read some post of those supporting SR theory. Sk oyuself which ae useful, and which are useless, which ae supportinmg for pure professional or personal reasons only. Which haven't a clue to what is occurring.

baffledmatt said:
Only the ps_strips and ergo their mutual distance to M' when the photons were emitted at t = 0 are of concern.

baffl4ed Matt, you keep referring o what " . . . the stationary observer sees the moving observer.." etc
If you agree that when M' is at M and this is the instant the photons are emitted from A and B is it not allowable to either insert the value '0' in a clock located at MM', a colocated coordinate set, say 0,0 in both frames? For confifdence we would want to 0 all clocks at all observation points. But for the ps-strip exposures I see no need for any clocks.

Certainly we can minimize the error sufficiently to negate any shrinking or time dilation problems.

I will accept your professional sense of honesty and let you iron out the engineering technicalities, it is your budget.

You want to go over this again, so be it. there is a ton of stuf in here baffled matt, a on. too much for mortals to digest in so short a time, unless one has an ephiphonous variance in their outlook. I have to tell you I am not equipped to take any prisoners.
 
  • #104
ram2048 said:
wow geist... harsh!

maybe not the best way to hold a discussion, but it's interesting in a JerrySpringer-esque kinda way :D


In an otherwise uneventful military hitch, I was talked to in what you would really call "harsh". No one manifested any overt symptoms of pathological eactions to this even though the nature of the conversation was intensely maintained for three months. I was taught to speak by an official of the US Givernment, a cruel and sadistic drill instructor. I speak "official" English.

I would apologize to Wespe if it weren't for the admonition by America's greatest thesbian of all time, John Wayne, who said, and very seriously too,: "Don't apologize, its a sign of weakness." Actually this probably wasn't original JW, but who cares at this juncture. Hell, I'll claim it as a Geistkiesel original and dare anyone to challenge me, well not anyone, but a lot of 'ones'. It is like my number 1 baseball hero, the worlds greatest, slickest and most effective baseball pitcher of all times, Leroy "Satchel" Paige, remarked" , "'When your enemy is stronger than you, walk him."
 
  • #105
Alkatran said:
An understanding and acceptance of relativity would probably help in understanding (or convincing, depending on your point of view.. how relative) that my simultanity isn't your simultanity.

I only said that even if those billions of people perceived the event, they wouldn't say it was simultaneous for others if they believed in relativity.
Then you're telling me I need not fear and uncontrolled spontaeous visit to bakerfield, Thats a relief.

I can comprehend believing in god and the tooth fairy and especially Santa Claus, I 've seen Santa Claus, but what physical significance do we place, ina scientific sense, what any number of people believe? I thought that was the reason scientists split off from the dictates of religious mythologicval dogma.
 
  • #106
Hurkyl said:
Keep in mind that the principle of relativity is part of classical mechanics; it was not invented by Einstein for the purpose of developing SR.



And to drive home the cosmological point about there being no good point of reference, consider these:

(1) Suppose in your future that we also considered a similar accident occurring on the streets of future earth. In this case, neither car was stationary with respect to the solar system!


(2) The guy who stopped was not at rest with respect to the rest of the universe. And, for instance, you might have been at rest with respect to the Milky Way. The important point is that a particular frame of reference was chosen (in this case, "at rest WRT the solar system"), so the traffic law is defined relative to this choice.


(3) What is "at rest in relation to the rest of the solar system" anyways? Things are moving in all sorts of directions, accelerating all over the place.

Not from the laws of physics do we intuit no absolute reference point but from the sheer technological chore of finding such a point. Even if the best instumentation conceivable were at our disposal and we were able to measure out to 20 billion light years and found a most perfect spot, it is the stellar entiities beyond 20 billion light years that would screw up the perfection. In any event we might perceive a need for a contacted and practical perfect rest point for some perceived need, for some finite duration of time. Ergo to within useful limits I see nio rule or law of physics preventing anyone from determining a relative point that does the job for the situation under consideration. i wouldn't tell any SR theorist about it though, no way. Read the posts, see what you would be subjecting yurself to?
 
  • #107
geistkiesel said, "Give us your veyr very best shot at analyzing the situation."

Sorry, the situation you're describing is too complicated to explain in one "shot". And your insistence that SR is wrong would doom to certain failure any attempt of mine to convince you otherwise!

But how about this? I'll explain it one step at a time. As long as you understand, and say that you believe, each step, I'll give you the next one. At the end you'll understand why SR is right and you were wrong.

You can agree to this by starting a new thread on the Relavitity Forum with the title "Why isn't the simultaneity of two events absolute?"

I'll be waiting!
 
  • #108
baffledMatt said:
Ok, so we have these film strips and after the experiment they will have two little dots on them corresponding to the points A and B when the photons were emitted. In the moving frame we measure the distance between these points using a metre ruler and come up with a length. We have (using my previous notation) that in the stationary frame the distance between A and B is 2L. However, due to Lorentz contraction the stationary observer will observe the moving observer to measure this distance to be 2L\gamma

NB
\gamma = \frac{1}{\sqrt(1-\frac{v^2}{c^2})} &gt; 1

This is because he sees the moving observer trying to measure a distance of 2L with a shorter (contracted) measuring stick. So he is observing the moving observer making a measurement larger than 2L.

The moving observer on the other hand sees the distance between A and B contracted. Hence, naively you might think he will measure a length of 2L/\gamma. This cannot be because what each observer sees must be the same (remember that we just had the stationary observer seeing the moving observer measure a longer length), so somehow the moving observer must also measure 2L\gamma. This happens because he does not observe the photon emissions to be simultaneous. Hence there is a little bit of time between the first and the second photon, which makes his measured length larger. This will ensure that his observation coincides exactly with that of the stationary observer.

Matt

No baffledMatt, why do you refer to stationary observers seeing what moving observer do. What is happenming in the physical wold. the language of SR is effectively limited to that used by yourself in this post. The observers perception, and when you take this down to thee eyeball to eyeball level of two observers in dfferent frames observing the same physical result, what do you get? Beside the confounding logic that I just must accept, what physical reality does one come up with? Four eyes seeing the same event, one sees it now and one sees it later, I think this is what you said implicitly at least. The stationary observer, "sees' the photons simultaneously emitted, because it is a given, ok take him to the where it us happeming and show him. Of course the stationary observer cannot observe both events simultabeously, he can only see one at a time. To make it easy on ourselves we postulated the simultaneous emission of photons in the stationsry frme.A photon in one place emits aT t1 and just across a wave length a moving observer sees the same physical 'even' later at time t2, which is also observed by the stationary observer. Me thinks this is a targeted point for SR logic, is it not?
 
  • #109
jdavel said:
ram2048 said, "it's a "Given" part of the experiment that they WERE emitted simultaneously as outlined in Einstein's original set up"

Not quite! They were simultaneous in the stationary frame, but, as it turns out, they weren't simultaneous in the moving frame. That's not an assumption; it's a conclusion based on the assumption that c is the same in both frames.

Here's "Einstein's original set up":

IN THE STATIONARY FRAME THE FLASHES ARE SIMULTANEOUS and are equidistant from the moving observer at the time of the flashes. So, the stationary observer sees light from the two flashes reach the moving observer at different times.

The moving observer agrees, light from the two flashes reached him at different times. Then he looks at the marks that the flashes made on his train, sees they are at equidistant from his seat on the train. Since he knows that c was the same for the light of both flashes, he concludes that THE FLASHES WERE NOT SIMULTANEOUS IN THE MOVING FRAME.

You are 100% absolutely correct. I did not intend to imply differently. In the opening post of this thread I stipulated that SR would predict the events were not simultaneous in bot he frames.

Simulatneity is not measured by your, AE's gedun
jken, it is measured by whether the photons emitted at A and B simultaneously were emitted into the moving frame simultaneoulsy, and the events of the staggered arrival is used as "proof" that the event were not emitted simultaneously in the moving frame. I recognize there is a considerable difference in AE'a trivial example and modern use, but his model is used tioday to emophacize and explain points right?

But look at what AE was using to justify loss of simultabneoty: the reception of photons at different times after the photons were emitted. I see no "relativity" implications here. Take the situation one step farther than AE took. The different arrival times could have been considered by an alert and acute scientist.'" HMMM, two photons different times and places. If the photons were emitted simultaneously and I were moving then I would see one before the other. Or if the photons were emitted at different times I might see them arriving simultaneously at the moving fame or at different times and not know which was emitted first. AE didn't ahve to stop at the naive point in the analysis that SR theorists are quoting this very day, yours not the first.
 
  • #110
jdavel said:
geistkiesel said, "Give us your veyr very best shot at analyzing the situation."

Sorry, the situation you're describing is too complicated to explain in one "shot". And your insistence that SR is wrong would doom to certain failure any attempt of mine to convince you otherwise!

But how about this? I'll explain it one step at a time. As long as you understand, and say that you believe, each step, I'll give you the next one. At the end you'll understand why SR is right and you were wrong.

You can agree to this by starting a new thread on the Relavitity Forum with the title "Why isn't the simultaneity of two events absolute?"

I'll be waiting!
I didn't say Sr was wrong for th e purposes of this thread. I stipulated SR would pedict no simultaneity. What I would ask, is look at the gedunken used as a template for this thread. Discuss in a professsional way the apparent pardox of he observed emission simultaneously being observed nonssimultaneously in the moving frame. Use the measurement condition o of the thread. I've been living SR for a while now, I do not need another proof. I am convicned that you will come up with what eveybody else came up with, Talk about the thread hypo, i f you please,,and if you are able.
 
  • #111
baffledMatt said:
and I was just about to say exactly the same thing about your link.



Errrm, hello?

*pointing to the last post I made*

Matt
baffledMatt can you point out to me by argument or otherwise whe ehttp://frontiernet.net/~geistkiesel/index_files/ Elaborate or brief, just specifics please. Myself, I thought it original which it will probable remain , who would want to confiscate silly physics? Any hint to a specific flaw(S) would be greatfully appreciated. Thanx G
 
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  • #112
baffledMatt said:
No, if they are sending the same 1 second pulses to each other they will each observe exactly the same thing - either a slowing down of the pulses (red shift) or a speeding up (blue shift) depending whether they are moving toward each other or away from each other.



I still don't see exactly what you mean by this. Could you perhaps give me the dumbed down version of how exactly this is done? It's no good you saying 'using the same physics' since we evidently don't agree on exactly what the physics is!



I can see why you might think that - I remember having exactly these sorts of problems with SR. The way I would always go about solving these problems though was to sit down and just calculate the thing. To illustrate:
Let's make some definitions:
x : space coordinate in 'stationary' frame. x = 0 is the midpoint between A and B, which are located at x = -L and x = L respectively.

v : velocity of the moving observer relative to the stationary observer.

Ok, so now I will calculate what the 'stationary' observer sees. Note I am not going to use any SR as such. We first calculate the location of the point where the 'moving' observer and the light from A coincide. This happens at a time t_A after the light is emitted from A and the point where they meet we denote d_A. By equating the distance the light moves in this time to the distance the moving observer moves we have:

vt_A = d_A
ct_A = d_A + L
so
\frac{v}{c}(L + d_A) = d_A
and
d_A = \frac{\frac{v}{c}L}{(1-\frac{v}{c})}

Similarly, we can derive d_B which is the point where the moving observer meets the light from B
vt_B = d_B
ct_B = (L-d_B)
so
\frac{v}{c}(L-d_B) = d_B
and again
d_B = \frac{\frac{v}{c}L}{(1+\frac{v}{c})}

Evidently, d_A \neq d_B so the photons do not hit the moving observer at the same time/place.



Ok, now repeat the calculation above, but for the moving observer. The only SR result I want you to use is that each observer must observe the same value for the speed of light. If you do this you should see that you need things like time dilation and lack of simultaneity to resolve the observations.

Matt

I ain't gona do your calculations for you. Hurkyl conned me into one of those. But then he complimented me on my calualtions, which showed simple way to determine if thephotons e were whatever. I think he screwed up, by complimenting me on something that effectiely undermined his specific point there. My argument assumes SR. so the easy out is the rationalization for te apparent paradox of the simulatneous emission of photons in a stationary frame turn magically into nonsimultaneity by the mere presen e of an inertial frame other than stationary in the vicinity.
 
  • #113
baffledMatt, modify my two clocks with the same frequency. The new model was loaded on one ship, Its frequency is 10^10hz. Now they can tell which is which and who is moving slower or faster? assuming they each had acceleration history to share or acceleration history available in some form. I suppose they wouldn't need the different clock speeds then would they?
 
  • #114
still seems silly that SR prefers the conclusion that simultaneity is at fault and not personal perspective. it's much more logical to conclude that personal reality is skewed because of movement and calculate backwards to conform to what the rest of the (stationary) universe sees.

but that's one of the things that's a matter of opinion i think. <shrug>

in any case in terms of space and relative fixed points, i think it's imperative that 3 dimensional space be charted in order to be utilized.

when living on Earth it's easy to use relative fixed points for reference, we do it intuitively and almost instinctively daily, driving between the lines, walking on the sidewalk, sitting down on a chair instead of missing it and landing on the floor...

in space you're dealing with far less points of reference AND far greater possible speeds, so everything becomes that much bigger of a problem.

seems only a matter of time before we MUST define a system to all conform to in order to share this real estate.
 
  • #115
Doc Al's error!

In an earlier post in this thread, I made a sloppy statement. I accused poor geistkiesel of assuming that:

Doc Al said:
(1) The marks on the photo-sensitive strips (caused by the photon emissions) in the moving frame are equally spaced from the point M' (which passed M at the exact moment that the clock at M read t=0): Not true!
(2) That the moving observers detect the photon emissions as happening simultaneously: Not true!

Yes, he made those assumptions--but I had meant to mark the first one as true. That first statement should have read:
(1) The marks on the photo-sensitive strips (caused by the photon emissions) in the moving frame are equally spaced from the point M' (which passed M at the exact moment that the clock at M read t=0): True!
I had meant to contrast assumption 1 with assumption 2, but I messed it up.

Just for the record, moving frame would record the time and position of the photon emissions (on geistkeisel's photo-sensitive strips) as follows.

In the "stationary" frame (O), photons are emitted at A (x = -L; t = 0) and at B (x = L; t = 0). These flashes are simultaneous in the stationary frame. (I assume that A and B are a distance L from the midpoint M.)

In the moving frame (O'), the photon emissions are recorded on the strips at the following postions and times:

The photon emission from B is recorded at:
x&#039; = \gamma L
t&#039; = -\gamma \frac {vL}{c^2}

The photon emission from A is recorded at:
x&#039; = -\gamma L
t&#039; = \gamma \frac {vL}{c^2}​

Where, as usual, \gamma = 1/\sqrt{(1 - \frac{v^2}{c^2})}.

I apologize for adding any additional confusion to this discussion. (I will add a note to the earlier posts.)

Of course, as I said before, much of this discussion--with geistkiesel's extraneous assumptions--could be avoided by addressing Einstein's actual argument in his train gedanken experiment. Of couse, geistkiesel is unable (or unwilling) to do that.

Note added: Just because that first assumption happens to be true, does not mean that it is justified and can be merely assumed. On the contrary, both assumptions are arbitrary, unjustified, and most importantly extraneous to the simple argument of Einstein. Einstein makes no such assumptions in his demonstration that simultaneity must be relative.
 
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  • #116
geistkiesel said:
baffledMatt can you point out to me by argument or otherwise whe ehttp://frontiernet.net/~geistkiesel/index_files/ Elaborate or brief, just specifics please. Myself, I thought it original which it will probable remain , who would want to confiscate silly physics? Any hint to a specific flaw(S) would be greatfully appreciated. Thanx G

The is no physics in your link! You don't make any calculations so how can I judge it? Then I click on the link to the so-called analysis and there is just a tiny little calculation which has already assumed your point is correct.

I have tried to show you calculations in a way to help you understand how the whole thing works but you reply with:
I ain't gona do your calculations for you. Hurkyl conned me into one of those.

I mean, do you want to be helped? Sorry, but physicists are not philosophers. You have to do calculations to really understand things.

so the easy out is the rationalization for te apparent paradox of the simulatneous emission of photons in a stationary frame turn magically into nonsimultaneity by the mere presen e of an inertial frame other than stationary in the vicinity.

Why is this a paradox? where is the magic? You are the one trying to bring in fairies by demanding something 'is' or 'is not' simultaneous.

No baffledMatt, why do you refer to stationary observers seeing what moving observer do.

This is the crucial point. Imagine I am observing someone moving relative to me. I can watch everything he does, see him measure things with his own measuring devises etc. Now, there must be no discrepancy between the measurements he makes and the ones I observe him to make. It's just that the explanation to why he got the result he did will differ between our frames (I'll say that his measuring stick shrunk wheras he will say that the events were not simultaneous.)

As another example, try this one. Imagine we both have clocks, we know that when they are in the same inertial frame that they tick at exactly the same rate - and they stay like that (they are very good clocks!). Now, you are moving at a velocity v relative to me and at the moment you pass me (ie our x coordinates coincide) we synchronize the clocks - make sure they are telling exactly the same time at that point in time.

Now, you are moving relative to me and so I observe your clock as ticking slightly slower. However, since I am also (relativistically speaking) moving relative to you, you shall also observe my clock as going slower than yours. We each observe each other's clock as going slower. But this is fine, there is no disagreement as such because all I can say is "I observe your clock as slow", I don't know what you might be observing.

Ok, now imagine that you break your clock at time T by your clock. This is an event we must both agree on, when your clock had the small hand pointing at T you broke it. Now, I observe your clock as ticking slower than mine so my clock reads \gamma T at the point when you break it. In fact, as soon as I see your clock stop i stop mine also so we must again both agree on this measurement, we both see \gamma T on my clock.

However, now for the 'paradox'. In your frame you were observing my clock as running slower than yours! So you might reason that my clock ought to read T / \gamma. But it doesn't, it reads \gamma T and we can both see this.

Resolve the paradox.

Not quite. As we have an excess of ps-strips, we assure ourselves that whatever shrinking occurs, one strip will be colocated at A and B within a minimum acceptable errror.

But then your establishment of simultaneity will only be accurate to this same error. You say that you will use an excess of strips so this error will in fact be pretty huge. Thus the results will prove nothing.

The numbered ps-strips guarantees the location of mesurements being equal distant from M' established by relected laser measurements.

But how are you performing these measurements?! You are assuming that these are things you can simply measure and will give you your expected result QED. What you are forgetting is that SR is all about measurement! It's a fact that different observers measure different things. But they all observe the same events.

Do you see the subtlety? "The distance between the sources is 2L" is a measurement which observers can disagree on, as is "the emission was simultaneous". But "I measured the distance to be 2L" is an event. All observers will see me make this measurement and observe me getting the result I did. It is only the events which we all agree on.

The frame knows nothing of stationary observers, perceptions or even that an experiment is being conducted.

Yes it does. The frame is trying to measure events which occur in a different frame. I would say that therefore this frame must know a lot about the stationary observer.

Matt
 
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  • #117
ram2048 said:
in any case in terms of space and relative fixed points, i think it's imperative that 3 dimensional space be charted in order to be utilized.

when living on Earth it's easy to use relative fixed points for reference, we do it intuitively and almost instinctively daily, driving between the lines, walking on the sidewalk, sitting down on a chair instead of missing it and landing on the floor...

in space you're dealing with far less points of reference AND far greater possible speeds, so everything becomes that much bigger of a problem.

seems only a matter of time before we MUST define a system to all conform to in order to share this real estate.

This is then a purely legal issue, but has nothing to do with physics.

Matt
 
  • #118
to conform to what the rest of the (stationary) universe sees.

The universe of which I'm aware is full of objects traveling every which way, constantly accelerating to different directions, and without any nice, global structure into which everything fits.

So, there are two very problematic things about this idea; why should there be such a thing as a "stationary universe", and how do we tell what it sees?



in any case in terms of space and relative fixed points, i think it's imperative that 3 dimensional space be charted in order to be utilized.

when living on Earth it's easy to use relative fixed points for reference, we do it intuitively and almost instinctively daily, driving between the lines, walking on the sidewalk, sitting down on a chair instead of missing it and landing on the floor...

in space you're dealing with far less points of reference AND far greater possible speeds, so everything becomes that much bigger of a problem.

seems only a matter of time before we MUST define a system to all conform to in order to share this real estate.

And the point is that a reference frame is chosen, and then everything else is defined relative to that.

Relativity does not say that you're not allowed to choose a reference frame as a "standard"; it merely says that any reference frame would suffice.
 
  • #119
baffledMatt said:
This is then a purely legal issue, but has nothing to do with physics.

Matt

It sounds to me ram2048 is talking about the real estate of space. A need getting our story straight if we are ever going to make some serious ventures into the cosmos.. This is what I read and we all know about perceptions and observations do we not?
 
  • #120
stationary universes.

Hurkyl said:
The universe of which I'm aware is full of objects traveling every which way, constantly accelerating to different directions, and without any nice, global structure into which everything fits.

So, there are two very problematic things about this idea; why should there be such a thing as a "stationary universe", and how do we tell what it sees?

Why, is a good question, but where and how are more practical questions. For instance the midoint of the surface of an expanding EM sphere is spatially invariant left to its unperturbed own devices.

The midpoint between any two expanding EM spheres invariant and universal. Some stellar objects are (must be) situated such that measurements, using carefully selected the sperical midpoints, as an invariant and absolute location with respect to distant stellar obsject may be exploited.


Hurkyl said:
And the point is that a reference frame is chosen, and then everything else is defined relative to that.

Relativity does not say that you're not allowed to choose a reference frame as a "standard"; it merely says that any reference frame would suffice.

I'm glad Hurkyl said that. I agree, finally, on something.
 

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