- #1

Einstein Mcfly

- 162

- 3

1) AB--> A +B

2) B+C->D

etc.

then in the first case you've added a mole and in the second case you've removed a mole. Therefore, when I calculate the delta G for these steps, the sign of RT*ln(RT) should be positive in the first case and negative in the second case, correct? You won't get cancellation when you calculate the delta Gs and these corrections will tweek things by three or so kcal/mol. Am I on the right track here or am I missing something?

Thanks for any help you can give.