Here's a scenario about which I have doubt. Consider a transmission line which has a length λ/4 and which has open circuit at load end. The source resistance is zero. The source voltage be V(adsbygoogle = window.adsbygoogle || []).push({}); _{s}and the source frequency is sufficiently high to be considered as high frequency application . The line is perfectly loss-less (sorry for considering an ideal situation, I just am asking this to clear my basic concepts). My question is what will be the voltage standing wave patterns on the line ?

Now as we know the open circuit at load end will give us Γ_{L}(which is reflection coefficient at load end) = 1. So the voltage standing wave has voltage maxima , V_{max}= 2|V_{+}| and voltage minima , V_{min}= 0 . where |V_{+}| is the magnitude of the forward travelling wave. But interestingly in this scenario the voltage maxima occurs at load end and thus the voltage minima occurs at source end (as the length is λ/4) . So because of this V_{min}cant be zero but equals a finite quantity i.e the source voltage V_{s}. Also this leads to V_{max}and |V_{+}|being equal to infinite . So my doubt is what would be the voltage at other points on the standing wave. I personally think it is infinite at all pts except at the source end where it is V_{s}.

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I tried to simulate the situation on this http://www.amanogawa.com/archive/StandingWavePattern1/StandingWavePattern1-2.html" [Broken] but since it can't deal with infinities my doubt remained unsolved.On the applet ,|V_{+}| I got was a very large number instead of getting infinity.

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# Standing Wave pattern on an open circuited transmission line with length λ/4

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