The discussion centers on the phenomenon of standing waves on a string, specifically addressing why higher harmonics exhibit lower amplitudes compared to the fundamental frequency when excited by a mechanical vibrator. Key equations such as the general wave equation for nth-harmonic waves and the energy dissipation formula are referenced. The participants conclude that the amplitude of higher harmonics decreases due to geometric factors and energy dissipation in the air, with the energy transmitted being proportional to the square of the frequency.
PREREQUISITESPhysics students, mechanical engineers, and anyone interested in wave mechanics and the behavior of vibrating strings in musical instruments or mechanical systems.
For the n-th time: This wasn't my entire explanation, just one of the factors I mentioned that can play a role, since we are talking generally without specific data.coquelicot said:Yet, your explanation...