Standing Waves Problem with Unknown Mass

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SUMMARY

The discussion focuses on the standing waves problem, specifically addressing the concepts of harmonics and their relationship to string tension and wavelength. The participant questions the interpretation of "loops" as harmonics and discusses the formula L = 1/2λ + nλ/2 for the fourth harmonic in strings. Additionally, they attempt to solve for amplitude using the equation x = Acos(ωt) and express confusion over the solution provided. The correct interpretation of string tension, density, and wave velocity is emphasized as crucial for understanding the problem.

PREREQUISITES
  • Understanding of standing wave theory
  • Familiarity with harmonic frequencies in strings
  • Knowledge of wave equations, specifically x = Acos(ωt)
  • Concepts of tension, density, and wave velocity relationships
NEXT STEPS
  • Study the relationship between tension and wave velocity in strings
  • Learn about harmonic series and their mathematical representations
  • Explore the derivation of the wave equation x = Acos(ωt)
  • Investigate the effects of mass and tension on wavelength in standing waves
USEFUL FOR

Physics students, educators, and anyone studying wave mechanics, particularly those focusing on standing waves and harmonic analysis in strings.

NP04
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Homework Statement
See Image. Parts C and D
Relevant Equations
Part C.
v = λf
Harmonic numbers for springs

Part D.
x = Acos(ωt). ??? Not really sure what formula to use.
Part C.

First of all, I am not entirely sure what the problem means by "loops." (I see the loops, duh ;)) but I am not sure what quantity they represent. I am guessing it means harmonics, in which case M would have to be lessened to make a greater wavelength. This is because the extension of the string would be lessened as it is less taut. In the relation L = 1/2λ+nλ/2 (4th harmonic for strings), we see that the dividend is

Is this the correct way of thinking about this part?

Part D.

x = Acos(ωt) = Acos(2πf)
4 = Acos((2π)((2π/3)) converted 120 degrees to radians
4 = A(1)
A = 4
The solution says it is 1. I can't think of any alternative to solve this.

Thanks in advance.
 

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NP04 said:
not sure what quantity they represent.
What is the relationship between the length of each loop and the wavelength?
NP04 said:
the extension of the string would be lessened as it is less taut
That is not a useful way to look at it. You should be able to quote a formula relating tension, density and wave velocity.
 

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