Static Charge Induction: Rod and Sphere Experiment

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Homework Statement



e78-1341-443c-b923-f7d096e7756b&out=http%3A%2F%2Fwww3.0zz0.com%2F2013%2F08%2F13%2F17%2F522810097.png


Homework Equations


The Attempt at a Solution


I think it depends on induction so when the rod is brought close, the spheres will be positively charged. When they move away of it, A will get a negative charge "by induction" and B will get a positive one
 
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Ammar Qasim said:

Homework Statement



e78-1341-443c-b923-f7d096e7756b&out=http%3A%2F%2Fwww3.0zz0.com%2F2013%2F08%2F13%2F17%2F522810097.png


Homework Equations





The Attempt at a Solution


I think it depends on induction so when the rod is brought close, the spheres will be positively charged. When they move away of it, A will get a negative charge "by induction" and B will get a positive one

Hi Ammar Qasim, Welcome to Physics Forums.

Since the spheres are on insulated stands and the rod never contacts the spheres, charges can only move around, and no new charges will enter the system (conservation of charge). The two spheres start out neutral (zero net charge). Further, charge can only move where there is a conduction path. What does this tell you about the sum of the charges on the two spheres after they are made separate?

When the spheres are in contact and the rod is brought close, make an approximate sketch of the distribution of charges on the spheres. What will it look like?
 
gneill said:
Hi Ammar Qasim, Welcome to Physics Forums.

Since the spheres are on insulated stands and the rod never contacts the spheres, charges can only move around, and no new charges will enter the system (conservation of charge). The two spheres start out neutral (zero net charge). Further, charge can only move where there is a conduction path. What does this tell you about the sum of the charges on the two spheres after they are made separate?

When the spheres are in contact and the rod is brought close, make an approximate sketch of the distribution of charges on the spheres. What will it look like?

Hi gneill, thank you for help.
When rod is brought close the positive charge will move to A and the negative charge will move to B then A will be attracted to the rob holding the positive charge so the answer will be letter B. Did I get it ?
 
Ammar Qasim said:
Hi gneill, thank you for help.
When rod is brought close the positive charge will move to A and the negative charge will move to B then A will be attracted to the rob holding the positive charge so the answer will be letter B. Did I get it ?


No. What happened to the negative charge that you say moved to B? Where does it go if you say that sphere B ends up neutral while sphere A is positive?
 
Last edited:
gneill said:
No. What happened to the negative charge that you say moved to B? Where does it go is you say that sphere B ends up neutral while sphere A is positive?

Oh, you are right. the negative charge will remain at B so the answer will be letter (A)
 
Ammar Qasim said:
Oh, you are right. the negative charge will remain at B so the answer will be letter (A)


Looks good :smile:
 

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