Static Charge Induction: Rod and Sphere Experiment

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Homework Help Overview

The discussion revolves around the concept of static charge induction in an experiment involving two spheres and a charged rod. Participants are exploring how charges redistribute when the rod is brought close to the spheres, which are initially neutral and placed on insulated stands.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants discuss the process of charge induction, questioning how charges move between the spheres when the rod is near. They explore the implications of conservation of charge and the conditions under which charges can redistribute.

Discussion Status

The conversation is active, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the conservation of charge and the behavior of charges in the system, but there is no explicit consensus on the final outcome of the charge distribution.

Contextual Notes

Participants are considering the constraints of the experiment, such as the spheres being insulated and the rod not making contact with them, which affects how charges can move and interact.

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Homework Statement



e78-1341-443c-b923-f7d096e7756b&out=http%3A%2F%2Fwww3.0zz0.com%2F2013%2F08%2F13%2F17%2F522810097.png


Homework Equations


The Attempt at a Solution


I think it depends on induction so when the rod is brought close, the spheres will be positively charged. When they move away of it, A will get a negative charge "by induction" and B will get a positive one
 
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Ammar Qasim said:

Homework Statement



e78-1341-443c-b923-f7d096e7756b&out=http%3A%2F%2Fwww3.0zz0.com%2F2013%2F08%2F13%2F17%2F522810097.png


Homework Equations





The Attempt at a Solution


I think it depends on induction so when the rod is brought close, the spheres will be positively charged. When they move away of it, A will get a negative charge "by induction" and B will get a positive one

Hi Ammar Qasim, Welcome to Physics Forums.

Since the spheres are on insulated stands and the rod never contacts the spheres, charges can only move around, and no new charges will enter the system (conservation of charge). The two spheres start out neutral (zero net charge). Further, charge can only move where there is a conduction path. What does this tell you about the sum of the charges on the two spheres after they are made separate?

When the spheres are in contact and the rod is brought close, make an approximate sketch of the distribution of charges on the spheres. What will it look like?
 
gneill said:
Hi Ammar Qasim, Welcome to Physics Forums.

Since the spheres are on insulated stands and the rod never contacts the spheres, charges can only move around, and no new charges will enter the system (conservation of charge). The two spheres start out neutral (zero net charge). Further, charge can only move where there is a conduction path. What does this tell you about the sum of the charges on the two spheres after they are made separate?

When the spheres are in contact and the rod is brought close, make an approximate sketch of the distribution of charges on the spheres. What will it look like?

Hi gneill, thank you for help.
When rod is brought close the positive charge will move to A and the negative charge will move to B then A will be attracted to the rob holding the positive charge so the answer will be letter B. Did I get it ?
 
Ammar Qasim said:
Hi gneill, thank you for help.
When rod is brought close the positive charge will move to A and the negative charge will move to B then A will be attracted to the rob holding the positive charge so the answer will be letter B. Did I get it ?


No. What happened to the negative charge that you say moved to B? Where does it go if you say that sphere B ends up neutral while sphere A is positive?
 
Last edited:
gneill said:
No. What happened to the negative charge that you say moved to B? Where does it go is you say that sphere B ends up neutral while sphere A is positive?

Oh, you are right. the negative charge will remain at B so the answer will be letter (A)
 
Ammar Qasim said:
Oh, you are right. the negative charge will remain at B so the answer will be letter (A)


Looks good :smile:
 

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