Static equilibrium and a diving board

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SUMMARY

The discussion focuses on the calculation of forces in a static equilibrium scenario involving a diving board. The support force at the left end is calculated to be -192.0 N, indicating an upward direction, while the force at the right end is determined to be 114.0 N, acting downwards. The calculations utilize torque equations to establish equilibrium, confirming the accuracy of the entered magnitudes and signs for the forces involved.

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Homework Statement
A diving board of length 3.00 m is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end (Figure 1). The diving board is of uniform cross section and weighs 280 N.
Find the magnitude of the force at the support point and its direction.
Find the magnitude of the force at the left-hand end and its direction.
Relevant Equations
##\sum\tau=0##
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I take the left end as reference for torques:
$$\sum\tau=F_\text{support}+\frac 32\times280+3\times500=0\Leftrightarrow F_\text{support}=-192.\times10^1\,N$$
It's facing up.
I take the right end as reference for torques:
$$\sum\tau=-192.\times10^1\times2+\frac 32\times280+3F=0\Leftrightarrow F=114.\times10^1\,N$$
Its direction is downwards.
 
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It's correct, I entered the MAGNITUDE of the support force with a SIGN. Goodbye marks.
 
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