1. The problem statement, all variables and given/known data A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 5.0 g stacked over the 12.0 cm mark, the stick is found to balance at the 45.5 cm mark. What is the mass of the meter stick? 2. Relevant equations netF = 0 netTorque = 0 The answer is 74 g 3. The attempt at a solution I know there is an upward force exerted by the knife, a downward force exerted by the weight of the coins, and another downward force exerted by gravity acting on the meter stick itself, which I originally thought was at the .5 mark. Does there need to be a second upward force at the .445 m mark, or is that where I put my pivot point? This shouldn't be a hard problem, but I don't think I really understand how the force diagram should look.