A window cleaner of mass 95 kg places a 22-kg ladder against a frictionless wall at an angle of 65 degrees with the horizontal. The ladder is 10m long and rests on a wet floor with a coefficient of static friction equal to 0.40. What is the maximum length that the window cleaner can climb before the ladder slips?
T = rF
The Attempt at a Solution
Sin65 = opp/10, therefore opposite = 9.06
Cos65 = adj/10, therefore adjacent = 4.23
m = 22; M=95
Max Ffr = uFN = u(mg + Mg) = Fw
Any help is appreciated!