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## Homework Statement

A window cleaner of mass 95 kg places a 22-kg ladder against a frictionless wall at an angle of 65 degrees with the horizontal. The ladder is 10m long and rests on a wet floor with a coefficient of static friction equal to 0.40. What is the maximum length that the window cleaner can climb before the ladder slips?

## Homework Equations

T = rF

## The Attempt at a Solution

Sin65 = opp/10, therefore opposite = 9.06

Cos65 = adj/10, therefore adjacent = 4.23

m = 22; M=95

Max F

_{fr}= uF

_{N}= u(mg + Mg) = F

_{w}

F

_{y}=F

_{N}-mg-Mg

T=F

_{w}(9.06)-mg(4.23/2)

Any help is appreciated!