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Static Equilibrium with a beam and cable
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[QUOTE="Juniper7, post: 4758472, member: 511485"] [h2]Homework Statement [/h2] A uniform vertical beam of mass 40kg is acted on by a horizontal force of 520N at its top and is held, in the vertical position, by a cable as shown in the attached picture. a) Calculate the tension in the cable b) Determine the reaction forces acting on the beam by the ground [h2]Homework Equations[/h2] F=T-mg [h2]The Attempt at a Solution[/h2] I think I over simplified this: ∑F[SUB]x[/SUB] = F[SUB]cable[/SUB]cos28° - F[SUB]applied force[/SUB] = 0 F[SUB]c[/SUB]cos28° = F[SUB]a[/SUB] F[SUB]c[/SUB] = 588.94N <---- answer to a) ∑F[SUB]y[/SUB] = F[SUB]c[/SUB]sin28° + mg - F[SUB]N[/SUB] = 0 F[SUB]c[/SUB]sin28° + mg = F[SUB]N[/SUB] (588.94N)sin28° + (40kg)(9.81m/s[SUP]2[/SUP]) = F[SUB]N[/SUB] F[SUB]N[/SUB] = 668.49N <----- answer to b) Thank you in advance for any help! [/QUOTE]
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Static Equilibrium with a beam and cable
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