1. The problem statement, all variables and given/known data A uniform vertical beam of mass 40kg is acted on by a horizontal force of 520N at its top and is held, in the vertical position, by a cable as shown in the attached picture. a) Calculate the tension in the cable b) Determine the reaction forces acting on the beam by the ground 2. Relevant equations F=T-mg 3. The attempt at a solution I think I over simplified this: ∑Fx = Fcablecos28° - Fapplied force = 0 Fccos28° = Fa Fc = 588.94N <---- answer to a) ∑Fy = Fcsin28° + mg - FN = 0 Fcsin28° + mg = FN (588.94N)sin28° + (40kg)(9.81m/s2) = FN FN = 668.49N <----- answer to b) Thank you in advance for any help!