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## Homework Statement

A uniform vertical beam of mass 40kg is acted on by a horizontal force of 520N at its top and is held, in the vertical position, by a cable as shown in the attached picture.

a) Calculate the tension in the cable

b) Determine the reaction forces acting on the beam by the ground

## Homework Equations

F=T-mg

## The Attempt at a Solution

I think I over simplified this:

∑F

_{x}= F

_{cable}cos28° - F

_{applied force}= 0

F

_{c}cos28° = F

_{a}

F

_{c}= 588.94N <---- answer to a)

∑F

_{y}= F

_{c}sin28° + mg - F

_{N}= 0

F

_{c}sin28° + mg = F

_{N}

(588.94N)sin28° + (40kg)(9.81m/s

^{2}) = F

_{N}

F

_{N}= 668.49N <----- answer to b)

Thank you in advance for any help!