Static friction on banked curve

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Homework Help Overview

The discussion revolves around a problem in mechanics related to static friction on a banked curve. The original poster is attempting to determine the minimum coefficient of static friction required for a car to avoid skidding while traveling at a specified speed on a banked curve with a given radius.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster describes their attempts to calculate the angle of banking and the coefficient of static friction using equations of motion. Some participants suggest making a detailed drawing to clarify the forces involved, while others inquire about the calculations related to friction.

Discussion Status

The discussion includes attempts to clarify the setup and calculations involved in the problem. Some guidance has been offered regarding the importance of considering both the horizontal and vertical components of forces. The original poster indicates they have resolved their issue, but no explicit consensus or final solution has been reached among participants.

Contextual Notes

Participants are working under the constraints of a homework problem, which may involve specific assumptions about the conditions of the banked curve and the forces acting on the car. The original poster's calculations and the definitions of forces are under scrutiny.

runner2392
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If a curve with a radius of 89.0m is perfectly banked for a car traveling 71.0km/hr, what is the minimum coefficient of static friction for a car not to skid when traveling at 91.8km/hr?

I figured out theta = 24. 03degs from the equations F(normal)*cos(theta) = mg and F(normal)*sin(theta) = m(v^2/r).

Then to find mus, I tried: m(v^2/r) = F(normal)sin(theta) -F(static f). For F(normal) I substituted mg/cos(theta) but ultimately I got the incorrect answer. Can someone please help?
Thanks
 
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Make a drawing and show your work in detail, please. The static friction acts along the load: It contributes with its horizontal component to the centripetal force, and its vertical component has to be taken into account in the equation for the vertical force components.

ehild
 
How did you calculate with the friction?

ehild
 
figured it out
 
Last edited:

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