Static friction on inclined surface

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Homework Help Overview

The problem involves static friction on an inclined surface, specifically calculating the coefficient of static friction required to prevent a boy from falling down a slope while being supported by a cord. The scenario includes a boy with a specified mass on a slope with a given angle.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the boy, including gravitational force down the slope, normal force, and frictional force. There is an exploration of the relationship between these forces and the breaking strength of the cord.

Discussion Status

Some participants have provided equations relating to the forces involved and have attempted to clarify the conditions under which the boy would not fall. There is an ongoing exploration of the equations and their implications, with no explicit consensus reached on the final approach.

Contextual Notes

Participants are working within the constraints of the problem, including the mass of the boy, the angle of the slope, and the breaking strength of the cord. There is a focus on ensuring that the forces are balanced to prevent falling.

drkidd22
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Hello all.

I'm having issues trying to figure out the following problem.

A boy with a mass of 52 kg and on a 56-degree slope is hanging on to a cord with a breaking strength of 152 Newtons. What must be the coefficient of static friction between the boy and the surface?
 
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force down the slope:
Fd = mg sin 560

normal force:
N = mg cos 560

Friction holding the boy
Fr = [tex]\mu[/tex]N

maximum force provided by string
Fs = 152

Equating forces:
the string must not break so the boy doesn't fall, so
Fd [tex]\leq[/tex] [tex]\mu[/tex]N + Fs

you can the solve for [tex]\mu[/tex], the coefficient of friction

Hope this is correct and helps
 
This works well. I had gotten almost everything together. The only thing I couldn't figure out was the equation of the forces.

Thanks for your help.
 
well, i was just being a little bit fancy

if you want, i think you can use

Fd = [tex]\mu[/tex]N + Fs

the previous equation:
Fd [tex]\leq[/tex] [tex]\mu[/tex]N + Fs
just means that the force pulling the boy down must be less than or equal to the force holding the boy up (Fr and Fs)
The only unknown variable is [tex]\mu[/tex], so as long as [tex]\mu[/tex] is big enough so that friction force is big, the boy would not fall.
 

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