Static friction on inclined surface

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drkidd22
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Hello all.

I'm having issues trying to figure out the following problem.

A boy with a mass of 52 kg and on a 56-degree slope is hanging on to a cord with a breaking strength of 152 Newtons. What must be the coefficient of static friction between the boy and the surface?
 
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force down the slope:
Fd = mg sin 560

normal force:
N = mg cos 560

Friction holding the boy
Fr = [tex]\mu[/tex]N

maximum force provided by string
Fs = 152

Equating forces:
the string must not break so the boy doesn't fall, so
Fd [tex]\leq[/tex] [tex]\mu[/tex]N + Fs

you can the solve for [tex]\mu[/tex], the coefficient of friction

Hope this is correct and helps
 
This works well. I had gotten almost everything together. The only thing I couldn't figure out was the equation of the forces.

Thanks for your help.
 
well, i was just being a little bit fancy

if you want, i think you can use

Fd = [tex]\mu[/tex]N + Fs

the previous equation:
Fd [tex]\leq[/tex] [tex]\mu[/tex]N + Fs
just means that the force pulling the boy down must be less than or equal to the force holding the boy up (Fr and Fs)
The only unknown variable is [tex]\mu[/tex], so as long as [tex]\mu[/tex] is big enough so that friction force is big, the boy would not fall.