Static friction on inclined surface

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SUMMARY

The discussion focuses on calculating the coefficient of static friction required to prevent a 52 kg boy from sliding down a 56-degree slope while hanging onto a cord with a breaking strength of 152 Newtons. The forces involved include the gravitational force down the slope (Fd = mg sin 56°), the normal force (N = mg cos 56°), and the frictional force (Fr = μN). The critical relationship established is Fd ≤ μN + Fs, where Fs is the maximum force provided by the string. The solution confirms that as long as the coefficient of friction (μ) is sufficiently high, the boy will not fall.

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  • Understanding of basic physics concepts such as forces and friction.
  • Knowledge of trigonometric functions (sine and cosine) as applied to inclined planes.
  • Familiarity with Newton's laws of motion.
  • Ability to manipulate algebraic equations to solve for unknowns.
NEXT STEPS
  • Study the derivation of friction equations in physics textbooks.
  • Learn about the applications of static friction in real-world scenarios.
  • Explore advanced topics in mechanics, such as dynamics on inclined planes.
  • Investigate the effects of different materials on the coefficient of static friction.
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drkidd22
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Hello all.

I'm having issues trying to figure out the following problem.

A boy with a mass of 52 kg and on a 56-degree slope is hanging on to a cord with a breaking strength of 152 Newtons. What must be the coefficient of static friction between the boy and the surface?
 
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force down the slope:
Fd = mg sin 560

normal force:
N = mg cos 560

Friction holding the boy
Fr = \muN

maximum force provided by string
Fs = 152

Equating forces:
the string must not break so the boy doesn't fall, so
Fd \leq \muN + Fs

you can the solve for \mu, the coefficient of friction

Hope this is correct and helps
 
This works well. I had gotten almost everything together. The only thing I couldn't figure out was the equation of the forces.

Thanks for your help.
 
well, i was just being a little bit fancy

if you want, i think you can use

Fd = \muN + Fs

the previous equation:
Fd \leq \muN + Fs
just means that the force pulling the boy down must be less than or equal to the force holding the boy up (Fr and Fs)
The only unknown variable is \mu, so as long as \mu is big enough so that friction force is big, the boy would not fall.
 

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