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Statics: Method of Joints (Truss)

  1. Mar 26, 2017 #1
    Can someone explain to me why that highlighted force is 0?
    moj.JPG

    2. Relevant equations
    ∑Fx = 0

    3. The attempt at a solution
    I found FDC to be 780lb and I am still trying to solve for FDE
     
  2. jcsd
  3. Mar 26, 2017 #2

    PhanthomJay

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    If BD was non zero, let's just say for example it was 100 pounds , then 100 lbs in the opposite direction would be required for equilibrium along that axis. Where would that required opposite force go?
     
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