Statics, Stress, and Machine design

Click For Summary
SUMMARY

The discussion focuses on solving for the force P in a statics problem involving equilibrium conditions. The user outlines the equations for equilibrium, specifically the summation of forces in the x and y directions, which are critical for determining P. Additionally, the user references the Safety Factor equation to find the minimum diameter of rod AB, which is contingent upon knowing the value of P. The discussion emphasizes the importance of understanding equilibrium and moment equations to derive the necessary values for further calculations.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with force summation equations in two dimensions
  • Knowledge of stress and safety factor calculations
  • Basic proficiency in mechanics of materials
NEXT STEPS
  • Study the concept of static equilibrium in two dimensions
  • Learn how to apply the summation of moments to solve for unknown forces
  • Explore the calculation of minimum rod diameters using safety factors
  • Investigate the implications of double shear in mechanical design
USEFUL FOR

Mechanical engineering students, structural engineers, and anyone involved in machine design or statics analysis will benefit from this discussion.

jmm21242
Messages
2
Reaction score
0

Homework Statement


I have attached a copy of the assignment problem. I have been having serious trouble finding the value of the force P. I know the equations to use for part b and c but I need to know the force P to complete the rest of the problem.

Homework Equations


a) The problem tells me that the object is in equilibrium so I know that the summation of the forces in the x and y direction are zero.
\SigmaF(x)=0=Fc-P
\SigmaF(y)=0=Fc-15kN-50kN

I don't know what other equations I can derive from this to help me solve for P

b) I know that to find the minimum diameter of the rod AB i will use the equation:
Safety Factor=stress to failure/stress allowed=>600 MPa/(Fmax/Area)

From here I can derive the value of the diameter of the rod if I know the value of P

c) I believe that part c is the same equation as part b please let me know if I am wrong on this.

The Attempt at a Solution


I would try and make an attempt but I can not make an attempt mathematically without first knowing how to do part A. I understand the equations for part b and c but do not know how I would solve to force P.
 

Attachments

  • 3_1 1166 #1.gif
    3_1 1166 #1.gif
    55.3 KB · Views: 903
Physics news on Phys.org
jmm21242 said:

Homework Statement


I have attached a copy of the assignment problem. I have been having serious trouble finding the value of the force P. I know the equations to use for part b and c but I need to know the force P to complete the rest of the problem.


Homework Equations


a) The problem tells me that the object is in equilibrium so I know that the summation of the forces in the x and y direction are zero.
\SigmaF(x)=0=Fc-P
\SigmaF(y)=0=Fc-15kN-50kN

I don't know what other equations I can derive from this to help me solve for P

b) I know that to find the minimum diameter of the rod AB i will use the equation:
Safety Factor=stress to failure/stress allowed=>600 MPa/(Fmax/Area)

From here I can derive the value of the diameter of the rod if I know the value of P

c) I believe that part c is the same equation as part b please let me know if I am wrong on this.



The Attempt at a Solution


I would try and make an attempt but I can not make an attempt mathematically without first knowing how to do part A. I understand the equations for part b and c but do not know how I would solve to force P.
Watch subscripts when looking in x and y directions, P = Fcx and Fcy is 65. Then you want to look at the 3rd equilibrium equation, sum of moments about C (or any point) = 0.

Once you now solve for Fc using Pythagorus, the pin is in double shear...
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K