[Statistics] measuring values against known value

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SUMMARY

The discussion centers on calculating the 95% confidence limit for the mean using a standard gram weight to assess the accuracy of a balance. The user initially attempted to solve the problem without considering the known weight, leading to confusion. Upon clarification, it was established that a one-sample t-test is the appropriate statistical method to apply in this scenario. The correct formula to use is ts/n^1/2, where 't' represents the t-score and 'n' is the sample size.

PREREQUISITES
  • Understanding of one-sample t-tests
  • Familiarity with confidence intervals
  • Knowledge of mean and standard deviation calculations
  • Basic grasp of statistical significance
NEXT STEPS
  • Study the application of one-sample t-tests in statistical analysis
  • Learn how to calculate confidence intervals using sample data
  • Explore the concept of degrees of freedom in statistical tests
  • Review the implications of known values in hypothesis testing
USEFUL FOR

Students in statistics, researchers conducting experiments, and anyone involved in quality control measurements requiring accuracy verification of balances.

Chickenpoxpie
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Homework Statement


You use a standard gram weight of known weight (x) to check the accuracy of a balance. For one balance, this standard is weighed 3 times yielding the following values; a, b, and c. Calculate the 95% confidence limit for the mean


Homework Equations


general statistics and mean equations
ts/n^1/2

The Attempt at a Solution


I am confused how to do this problem because of the known value. At first I did the problem ignoring the known value and going through all the motions (figuring the mean, standard dev, and then plugging into ts/n^1/2 for 2 degrees of freedom) but how do things change because of the known weight and "testing for the accuracy of the balance"?
 
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Nevermind y'all, was a silly mistake. I can easily do a one sample t test
 

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