Statistics average value question

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SUMMARY

The discussion centers on the mathematical proof of the inequality A(X(ωk)²) ≥ A(X(ωk))², which holds true if and only if the random variable X(ωk) takes the same value for all k where pk > 0. The equation A(X) = 1/N ∑nk X(ωk) = ∑pk X(ωk) is critical in establishing this relationship. The user expresses concern that the question is poorly structured, as the derived inequality A(X²) - A(X)² suggests that A(X²) must be greater than or equal to A(X)² for all X(ωk), given that variance cannot be negative. The user proposes that the question likely omits the phrase "... with equality if and only if ...".

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  • Understanding of statistical expectations, specifically A(X) and A(X²).
  • Familiarity with the concept of variance in probability theory.
  • Basic knowledge of random variables and their properties.
  • Ability to interpret mathematical inequalities and proofs.
NEXT STEPS
  • Review the concept of variance and its implications in statistics.
  • Study the properties of expected values and their relationships.
  • Learn about the conditions for equality in statistical inequalities.
  • Explore examples of well-structured statistical problems to identify common pitfalls.
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kidsasd987
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Homework Statement



Prove that A(X(ωk)2)≥A(X(ωk))2 if and only if X(ωk) has the same value for every k such that pk>0 for every category which actually occurs in the population

Homework Equations


A(X)=1/N∑nkX(ωk)=∑pkX(ωk)

The Attempt at a Solution


A[(X-A(X)2)]=A(X2)-A(X)2

and i believe the question itself is ill-structured because A(X2)-A(X)2 implies A(X2)≥A(X)2 for all X(ωk) since variance cannot be a negative value. Please confirm with me. Thanks
 
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The intended question is probably missing the statement "... with equality if and only if ..."
 

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