Statistics, ping pong balls in bag probability question

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Discussion Overview

The discussion revolves around a probability problem involving the selection of colored ping-pong balls from a bag. Participants are exploring how to calculate the probability that two randomly selected balls are of the same color, with a focus on the correct application of probability rules.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • Calculator14 proposes a formula for calculating the probability of selecting two balls of the same color, suggesting that it can be expressed as the sum of the probabilities for each color.
  • Calculator14's calculation includes terms for the probabilities of selecting red, blue, and green balls, but the method of combining these probabilities is questioned.
  • tiny-tim challenges the multiplication approach used by Calculator14, asking for clarification on the reasoning behind it and suggesting a need to start over with the calculation.
  • tiny-tim specifically asks for the probability of selecting two blue balls as a starting point for the discussion.

Areas of Agreement / Disagreement

Participants do not appear to agree on the method for calculating the probability, with differing opinions on whether to multiply or add probabilities. The discussion remains unresolved regarding the correct approach.

Contextual Notes

There are uncertainties regarding the application of probability rules, particularly in how to combine the probabilities for different colors. The initial calculations presented may depend on assumptions that are not fully articulated.

Who May Find This Useful

This discussion may be useful for students learning about probability, particularly in the context of combinatorial problems and the selection of items from a set.

Calculator14
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Homework Statement



Twelve colored ping-pong balls are placed into a shopping bag and well mixed. There are two red balls, six blue balls and four green balls. One ball is selected at random, its color noted and then it is set aside. A second ball is then randomly selected and its color noted. What is the probability that both balls are the same color?

Homework Equations



P(two same color) = P(red) + P(blue) + P(green)

The Attempt at a Solution



P(two same color) = (2/12 + 1/12) * (6/12 + 5/12) * (4/12 + 3/12) = .8125
 
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Hi Calculator14! :smile:
Calculator14 said:
P(two same color) = P(red) + P(blue) + P(green)

The Attempt at a Solution



P(two same color) = (2/12 + 1/12) * (6/12 + 5/12) * (4/12 + 3/12) = .8125

I don't understand :redface:

why are you multiplying instead of adding?

and eg what is 6/12+5/12 supposed to be? :confused:

Start again …

what is P(both balls are blue)? :smile:
 
Hi tiny-tim! I'm sorry, I am lost on how to start this equation. Would you be able to guide me a bit through this? Thank you for your help!
 
Hi Calculator14! :smile:

(just got up :zzz: …)

If you select two balls out of 12, what is the probability that both balls are blue?
 

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