Steel - Youngs Modulus, Poisson Ratio

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SUMMARY

The discussion focuses on calculating the deformation of a steel grade with a Young's Modulus of 200 GPa and a Poisson Ratio of 0.3 under a load of 10 tonnes. The formula E = σ/ε is highlighted for determining strain (ε), which is essential for calculating changes in length. Additionally, the application of Hooke's Law in two dimensions is mentioned for assessing the change in width. The steel's dimensions include a length of 2m and a cross-sectional area of 20mm².

PREREQUISITES
  • Understanding of Young's Modulus and its application in material science.
  • Familiarity with Poisson's Ratio and its significance in deformation analysis.
  • Knowledge of Hooke's Law and its application in both one and two dimensions.
  • Basic principles of tensile strength and its relevance to structural integrity.
NEXT STEPS
  • Research the application of Young's Modulus in different materials beyond steel.
  • Learn about advanced calculations involving Poisson's Ratio in composite materials.
  • Explore practical examples of Hooke's Law in engineering scenarios.
  • Investigate the effects of varying loads on the deformation of structural steel elements.
USEFUL FOR

Engineers, material scientists, and students studying mechanical properties of materials will benefit from this discussion, particularly those focused on structural analysis and deformation calculations in steel.

samirnasri
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Hello,

Quick question on how you would go about calculating this.

A grade of steel has the following properties;

Tensile strength = 300 N/mm^2 - (not relevant?)
Youngs Modulus = 200 GPa
Poisson Ratio = 0.3

The grade of steel is 2m long, with a 20mm cross sectional area.

It is positioned upright and supports a load of 10 tonnes.

How would you calculate how much shorter or wider it becomes?

Thank you
 
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You should know that E= σ/ε where you can get ε from and hence get the change in length.

To get how wide it becomes, what is Hooke's law in 2 dimensions?
 

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