Step-by-Step Guide to Solving Differential Equations | Expert Tips and Tricks

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Discussion Overview

The discussion revolves around solving differential equations related to circuit analysis. Participants explore various methods and approaches to arrive at a solution, with a focus on specific examples and the challenges faced in the process.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant expresses difficulty in solving a differential equation and seeks guidance on the steps to reach the provided answer.
  • Another participant encourages sharing attempted methods and points of confusion to facilitate assistance.
  • A participant suggests using node analysis and simplifying with impedance to approach the problem.
  • There is a clarification regarding the notation used, specifically the meaning of "D" as d/dt.
  • Participants discuss the replacement of circuit components with impedances and the implications for solving the equation.
  • One participant indicates they have worked through the problem but did not arrive at the expected result, prompting further inquiry into their process.
  • Ultimately, a participant claims to have solved the problem after multiple attempts and expresses willingness to share their solution.

Areas of Agreement / Disagreement

The discussion reflects a lack of consensus on the methods used to solve the differential equation, with multiple participants offering different approaches and expressing uncertainty about the effectiveness of those methods.

Contextual Notes

Participants reference specific examples and resources, but the discussion does not resolve the underlying assumptions or steps taken in the problem-solving process.

Who May Find This Useful

Students and individuals interested in circuit analysis and differential equations may find the discussion relevant, particularly those seeking collaborative problem-solving approaches.

xmenus
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Hi ,
Can anyone help me on this problem please?!
Answer is given but i want to know steps to come to it, i think i tried a lot to solve it but i couldn't come to the given result.
Thanks to all
 

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hi xmenus! welcome to pf! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Here's the link of doc..I think i tried loop method and many other forms but... here i just showed the analogy i tried but i couldn't come to the result.(First circuit is different one)
I took an other example just to show or ask if the other circuit can be solved with the same analogy?!

https://www.dropbox.com/sh/7g4vmpl4uhjbyl4/wwNdGrKm5o
 
Last edited:
it's rather difficult to read :redface:

anyway, what is D ? :confused:​
 
That's a tough circuit you posted for finding a differential equation.

Don't know for sure...but perhaps a node analysis on the upper right hand node? Current in equal current out sort of thing.

Using SL and 1/(SC) may simplify things as well.
 
xmenus said:
I took an other example just to show or ask if the other circuit can be solved with the same analogy?!

ah, D = d/dt !

ok, you've replaced C and R3 (in series) by an impedance Z1

(btw, wouldn't Z3 be an easier name to keep track of? :wink:)

then you've replaced R2 and Z1 (in parallel) by Ze

but then you've stopped (presumably you're going to replace L and Ze, then replace that and R1?)

well, that looks fine so far :smile: …

what's the difficulty?​
 
The problem is that it's not working like that.I can't come to the result, i don't know!?
 
but you stopped, you only got as far as Ze :confused:
 
  • #10
No,actually i worked on it till to the end but the result i got is not like the given one.
You are right, i didnt post other steps,but on that way it didnt work!
 
  • #11
we can't comment on why it didn't work unless you show us what you did
 
  • #12
Finally,after many attempts, i solved it :D !

I might post the solution so anyone can find it useful maybe.
Thank you a lot anyway,and thank for your time!
 
Last edited:
  • #13
Solution is in .pdf file.

Regards
 

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